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Molecule Parameter List for CaM-Ca4

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca4 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000031

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
CaMKII_200349Network
Shared_Object_CaMKII_2003,  CaMKII,  CaM,  
PP1,  PP2B 
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal.
Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaM-Ca4 acting as a Molecule in  CaMKII_2003 Network
NameAccession NamePathway NameInitial Conc.
(uM)		Volume
(fL)		Buffered
CaM-Ca4CaMKII_2003
Accession No. : 49
  • Shared_Object_
    CaMKII_2003
    Pathway No. : 201
    		• 01000No

    CaM-Ca4 acting as a Substrate in a reaction in      CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1CaMKII-bind-CaMCaMKII_2003
    Accession No. : 49    		CaMKII
    Pathway No. : 202    		49.9998
    (uM^-1 s^-1)    		5
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    CaM-Ca4
    CaMKII

    Product
    CaMKII-CaM
      This is tricky. There is some cooperativity here arising from interactions between the subunits of the CAMKII holoenzyme. However, the stoichiometry is 1. Kb/Kf = 6e4 #/cell. Rate is fast (see Hanson et al Neuron 12 943-956 1994) so lets say kb = 10. This gives kf = 1.6667e-4 H&S AnnRev Biochem 92 give tau for dissoc as 0.2 sec at low Ca, 0.4 at high. Low Ca = 100 nM = physiol.
    2
  • CaMK-thr286-bind
    -CaM
    		• CaMKII_2003
    Accession No. : 49    		CaMKII
    Pathway No. : 202    		1000.2
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0001(uM)-Substrate
    CaM-Ca4
    CaMKII-thr286

    Product
  • CaMKII-thr286*-C
    aM
    •   Affinity is up 1000X. Time to release is about 20 sec, so the kb is OK at 0.1 This makes Kf around 1.6666e-3
    3
  • CaMCa4-bind-CaNA
    B
    		• CaMKII_2003
    Accession No. : 49    		PP2B
    Pathway No. : 205    		600
    (uM^-1 s^-1)    		1
    (s^-1)    		Kd(bf) = 0.0017(uM)-Substrate
    CaM-Ca4
    CaNAB-Ca4

    Product
    CaMCa4-CaNAB

    CaM-Ca4 acting as a Product in a reaction in      CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    CaM-Ca3-bind-CaCaMKII_2003
    Accession No. : 49    		CaM
    Pathway No. : 203    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5054(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
    Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10


    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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