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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000021

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
CaMKII_200349Network
Shared_Object_CaMKII_2003 CaMKII CaM 
PP1 PP2B 
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal.
Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaM-Ca3 acting as a Molecule in  
CaMKII_2003 Network
NameAccession NamePathway NameInitial Conc.
(uM)
Volume
(fL)
Buffered
CaM-Ca3CaMKII_2003
Accession No. : 49
  • Shared_Object_
    CaMKII_2003

    Pathway No. : 201
  • 01000No

    CaM-Ca3 acting as a Substrate in a reaction in  
    CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1CaM-Ca3-bind-CaCaMKII_2003
    Accession No. : 49
    CaM
    Pathway No. : 203
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5054(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    2
  • CaMCa3-bind-CaNA
    B
  • CaMKII_2003
    Accession No. : 49
    PP2B
    Pathway No. : 205
    2.238
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 0.4468(uM)-Substrate
    CaM-Ca3
    CaNAB-Ca4

    Product
    CaMCa3-CaNAB

    CaM-Ca3 acting as a Product in a reaction in  
    CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
  • CaM-TR2-Ca2-bind
    -Ca
  • CaMKII_2003
    Accession No. : 49
    CaM
    Pathway No. : 203
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
    K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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