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Molecule Parameter List for Ca | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | | CaMKII_model3 | 63 | Network |
Shared_Object_CaMKII_model3, CaMKII, CaM,
PP1, PP2B, PP1_PSD,
AC, PKA | | This is the complete model of CaMKII bistability, model 3. It exhibits bistability in CaMKII activation due to autophosphorylation at the PSD and local saturation of PP1. This version of model 3 includes PKA regulatory input. This has little effect on the deterministic calculations, but the PKA pathway introduces a lot of noise which causes a difference in stochastic runs. |
Ca acting as a Molecule in CaMKII_model3 Network
Ca acting as a Substrate in a reaction in CaMKII_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| | Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | 1 | CaM-TR2-bind-Ca | CaMKII_model3
Accession No. : 63 | CaM
Pathway No. : 265 | 71.999
(uM^-2 s^-1) | 72
(s^-1) | Kd(af) = 1(uM) | - | Substrate
Ca
Ca
CaM
Product
CaM-TR2-Ca2
| | | Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !).... | | 2 | CaM-TR2-Ca2-bind
-Ca | CaMKII_model3
Accession No. : 63 | CaM
Pathway No. : 265 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate
Ca
CaM-TR2-Ca2
Product
CaM-Ca3
| | | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 | | 3 | Ca-bind-CaNAB-Ca
2 | CaMKII_model3
Accession No. : 63 | PP2B
Pathway No. : 267 | 3.6001
(uM^-2 s^-1) | 1
(s^-1) | Kd(af) = 0.527(uM) | - | Substrate
Ca
Ca
CaNAB-Ca2
Product
CaNAB-Ca4
| | | This process is probably much more complicated and involves CaM. However, as I can't find detailed info I am bundling this into a single step. Based on Steemer and Klee pg 6863, the Kact is 0.5 uM. kf/kb = 1/(0.5 * 6e5)^2 = 1.11e-11 | | 4 | Ca-bind-CaNAB | CaMKII_model3
Accession No. : 63 | PP2B
Pathway No. : 267 | 10008
(uM^-2 s^-1) | 1
(s^-1) | Kd(af) = 0.01(uM) | - | Substrate
Ca
Ca
CaNAB
Product
CaNAB-Ca2
| | | going on the experience with CaM, we put the fast (high affinity) sites first. We only know (Stemmer and Klee) that the affinity is < 70 nM. Assuming 10 nM at first, we get kf = 2.78e-8, kb = 1. Try 20 nM. kf = 7e-9, kb = 1 | | 5 | CaM-Ca3-bind-Ca | CaMKII_model3
Accession No. : 63 | Shared_Object_
CaMKII_model3
Pathway No. : 263 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
Ca acting as a Product in a reaction in CaMKII_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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