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Molecule Parameter List for Ca

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Ca participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences25000014949

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    		• 81NetworkShared_Object_Ajay_bhalla_2007_ReacDiff1_1e-12,  
    PKC,  MAPK,  Ras,  CaM,  PKM,  chain,  kinetics,  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[1],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[2],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[3],  
    PKC,  MAPK,  MAPK,  Ras,  CaM,  PKM,  kinetics[4],  PKC,  MAPK,  Ras,  CaM,  PKM,  
    kinetics[5],  PKC,  MAPK,  Ras,  kinetics[6],  CaM,  PKM,  PKC,  MAPK,  Ras,  
    CaM,  PKM,  kinetics[7],  PKC,  Ras,  CaM,  PKM,  kinetics[8],  PKC,  MAPK,  
    Ras,  CaM,  PKM,  kinetics[9],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[10],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[11],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[12],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[13],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[14],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[15],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[16],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[17],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[18],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[19],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[20],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[21],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[22],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[23],  PKC,  MAPK,  Ras,  CaM,  PKM 
    This is a 25-compartment reaction-diffusion version of the Ajay_Bhalla_2007_PKM model. The original single-compartment model is repeated 25 times. In addition, a subset (27 out of 42) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. For D = 1e-12 m^2/sec (i.e., 1 micron^2/sec ) the kf and kb of this reaction for these 10 micron compartments are both 0.01/sec. For D = 1e-13 m^2/sec (i.e., 0.1 micron^2/sec ) the kf and kb are 0.001/sec.
    The stimulus file pkm_mapk22_diff_1e-12_Fig4A which was used for the model to replicate Figure 4A from the paper.
    This stimulus file pkm_mapk22_diff_1e-12_Fig4G which was used for the model to replicate Figure 4G from the paper

    Ca acting as a Molecule in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)    		Volume
    (fL)    		Buffered
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics
    Pathway No. : 382    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[1]
    Pathway No. : 388    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[2]
    Pathway No. : 394    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[3]
    Pathway No. : 400    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[4]
    Pathway No. : 407    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[5]
    Pathway No. : 413    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[6]
    Pathway No. : 417    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[7]
    Pathway No. : 425    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[8]
    Pathway No. : 430    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[9]
    Pathway No. : 436    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[10]
    Pathway No. : 442    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[11]
    Pathway No. : 448    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[12]
    Pathway No. : 454    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[13]
    Pathway No. : 460    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[14]
    Pathway No. : 466    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[15]
    Pathway No. : 472    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[16]
    Pathway No. : 478    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[17]
    Pathway No. : 484    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[18]
    Pathway No. : 490    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[19]
    Pathway No. : 496    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[20]
    Pathway No. : 502    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[21]
    Pathway No. : 508    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[22]
    Pathway No. : 514    		0.081.5No
    Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[23]
    Pathway No. : 520    		0.081.5No

    Ca acting as a Substrate in a reaction in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 376    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    2CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    3CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    4CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    6diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    7PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 383    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    8CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    9CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    10CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    11CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    12diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    13PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 401    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    14PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 389    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    15CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    16CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    17CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    18CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    19diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    20PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 395    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    21CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    22CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    23CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    24CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    25diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    26PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 426    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    27CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    28CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    29CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    30CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    31diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    32PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 408    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    33CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    34CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    35CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    36CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    37diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    38PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 414    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    39CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    40CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    41CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    42CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    43diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    44PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 420    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    45CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    46CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    47CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    48CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    49diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    50PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 473    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    51CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    52CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    53CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    54CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    55diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    56PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 431    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    57CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    58CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    59CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    60CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    61diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    62PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 437    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    63CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    64CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    65CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    66CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    67diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    68PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 443    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    69CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    70CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    71CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    72CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    73diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    74PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 449    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    75CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    76CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    77CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    78CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    79diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    80PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 455    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    81CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    82CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    83CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    84CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    85diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    86PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 461    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    87CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    88CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    89CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    90CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    91diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    92PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 467    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    93CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    94CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    95CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    96CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    97diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    98CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    99CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    100CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    101CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    102diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    103PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 479    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    104CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    105CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    106CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    107CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    108diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    109PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 485    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    110CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    111CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    112CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    113CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    114diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    115PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 491    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    116CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    117CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    118CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    119CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    120diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    121PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 497    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    122CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    123CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    124CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    125CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    126diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    127PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 503    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    128CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    129CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    130CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    131CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    132diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    133PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 509    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    134CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    135CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    136CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    137CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    138diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    139PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 515    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    140CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    141CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    142CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    143CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    144diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    145PKC-act-by-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• PKC
    Pathway No. : 521    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    146CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    147CaM-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    148CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    149CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		8.4851
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853

    Ca acting as a Product in a reaction in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    2Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    3diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    4Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics
    Pathway No. : 382    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    5diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    6Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[1]
    Pathway No. : 388    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    7diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    8Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[2]
    Pathway No. : 394    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    9diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    10Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[3]
    Pathway No. : 400    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    11diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    12Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[4]
    Pathway No. : 407    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    13diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    14Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[5]
    Pathway No. : 413    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    15diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    16Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[6]
    Pathway No. : 417    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    17diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    18Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[7]
    Pathway No. : 425    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    19diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    20Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[8]
    Pathway No. : 430    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    21diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    22Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[9]
    Pathway No. : 436    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    23diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    24Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[10]
    Pathway No. : 442    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    25diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    26Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[11]
    Pathway No. : 448    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    27diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    28Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[12]
    Pathway No. : 454    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    29diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    30Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[13]
    Pathway No. : 460    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    31diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    32Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[14]
    Pathway No. : 466    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    33diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    34Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[15]
    Pathway No. : 472    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    35diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    36Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[16]
    Pathway No. : 478    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    37diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    38Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[17]
    Pathway No. : 484    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    39diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    40Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[18]
    Pathway No. : 490    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    41diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    42Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[19]
    Pathway No. : 496    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    43diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    44Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[20]
    Pathway No. : 502    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    45diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    46Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[21]
    Pathway No. : 508    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    47diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    Ca

    Product
    Ca
    48Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[22]
    Pathway No. : 514    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    49Ca_diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• kinetics[23]
    Pathway No. : 520    		5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca


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