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Molecule Parameter List for Ca

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Ca participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences25000015025

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_ReacDiff3
    		• 84NetworkShared_Object_Ajay_Bhalla_2007_ReacDiff3,  PKC,  PLA2,  
    MAPK,  PLA2,  Ras,  CaM,  chain,  kinetics,  PKC,  MAPK,  Ras,  CaM,  kinetics[1],  
    PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[2],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[3],  
    PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[4],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[5],  
    PKC,  PLA2,  MAPK,  Ras,  MAPK,  CaM,  kinetics[6],  PKC,  PLA2,  MAPK,  Ras,  
    CaM,  kinetics[7],  PKC,  PLA2,  MAPK,  Ras,  CaM,  PKC,  kinetics[8],  PLA2,  
    MAPK,  Ras,  CaM,  kinetics[9],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[10],  
    PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[11],  PKC,  PLA2,  MAPK,  Ras,  CaM,  
    kinetics[12],  PKC,  PLA2,  Ras,  CaM,  kinetics[13],  PKC,  PLA2,  MAPK,  
    Ras,  CaM,  kinetics[14],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[15],  
    PKC,  PLA2,  MAPK,  Ras,  kinetics[16],  CaM,  PKC,  PLA2,  MAPK,  Ras,  CaM,  
    kinetics[17],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[18],  PKC,  PLA2,  
    MAPK,  Ras,  CaM,  kinetics[19],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[20],  
    PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[21],  PKC,  PLA2,  MAPK,  Ras,  CaM,  
    kinetics[22],  PKC,  PLA2,  MAPK,  Ras,  CaM,  kinetics[23],  PKC,  PLA2,  
    MAPK,  Ras,  CaM 
    This is a 25-compartment reaction-diffusion version of the Ajay_Bhalla_2007_bistable model. The original single-compartment model is repeated 25 times.
    In addition, a subset (33 out of 50) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. Here D = 1e-13 m^2/sec (i.e., 0.1 micron^2/sec ) so the kf and kb of this reaction for these 10 micron compartments are both 0.001/sec.
    The basal calcium level in this model is held at 95 nM which is rather close to threshold for the flip to the active state. This is necessary to sustain active propagation of activation.
    The stimulus file bis6-propgn_D1e-13_FigEF which was used for the model to replicate Figure 4E and 4F from the paper.

    Ca acting as a Molecule in      Ajay_Bhalla_2007_ReacDiff3 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)    		Volume
    (fL)    		Buffered
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff3
    Pathway No. : 918
    		• 0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics
    Pathway No. : 926    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[1]
    Pathway No. : 931    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[2]
    Pathway No. : 937    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[3]
    Pathway No. : 943    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[4]
    Pathway No. : 949    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[5]
    Pathway No. : 955    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[6]
    Pathway No. : 962    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[7]
    Pathway No. : 968    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[8]
    Pathway No. : 975    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[9]
    Pathway No. : 980    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[10]
    Pathway No. : 986    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[11]
    Pathway No. : 992    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[12]
    Pathway No. : 998    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[13]
    Pathway No. : 1003    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[14]
    Pathway No. : 1009    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[15]
    Pathway No. : 1015    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[16]
    Pathway No. : 1020    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[17]
    Pathway No. : 1027    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[18]
    Pathway No. : 1033    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[19]
    Pathway No. : 1039    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[20]
    Pathway No. : 1045    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[21]
    Pathway No. : 1051    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[22]
    Pathway No. : 1057    		0.095125.7Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[23]
    Pathway No. : 1063    		0.095125.7Yes

    Ca acting as a Substrate in a reaction in      Ajay_Bhalla_2007_ReacDiff3 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 919    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    2PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 920    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    3PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 920    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    4CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 924    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    5
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 924    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    6CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 924    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    7PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 927    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    8PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 922    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    9PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 922    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    10CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 930    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    11
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 930    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    12CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 930    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    13PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 932    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    14PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 933    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    15PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 933    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    16CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 936    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    17
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 936    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    18CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 936    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    19PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 938    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    20PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 939    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    21PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 939    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    22CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 942    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    23
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 942    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    24CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 942    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    25PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 944    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    26PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 945    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    27PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 945    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    28CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 948    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    29
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 948    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    30CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 948    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    31PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 950    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    32PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 951    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    33PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 951    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    34CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 954    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    35
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 954    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    36CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 954    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    37PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 956    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    38PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 957    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    39PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 957    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    40PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1000    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    41CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 961    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    42
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 961    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    43CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 961    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    44PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 963    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    45PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 964    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    46PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 964    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    47CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 967    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    48
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 967    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    49CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 967    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    50PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 969    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    51PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 970    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    52PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 970    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    53CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 973    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    54
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 973    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    55CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 973    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    56PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 974    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    57PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 976    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    58PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 976    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    59CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 979    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    60
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 979    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    61CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 979    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    62PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 981    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    63PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 982    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    64PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 982    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    65CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 985    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    66
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 985    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    67CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 985    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    68PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 987    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    69PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 988    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    70PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 988    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    71CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 991    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    72
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 991    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    73CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 991    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    74PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 993    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    75PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 994    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    76PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 994    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    77CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 997    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    78
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 997    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    79CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 997    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    80PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 999    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    81PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1000    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    82CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1002    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    83
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1002    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    84CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1002    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    85PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1004    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    86PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1005    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    87PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1005    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    88CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1008    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    89
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1008    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    90CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1008    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    91PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1010    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    92PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1011    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    93PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1011    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    94CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1014    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    95
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1014    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    96CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1014    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    97PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1016    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    98PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1017    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    99PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1017    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    100CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1021    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    101
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1021    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    102CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1021    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    103PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1022    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    104PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1023    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    105PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1023    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    106CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1026    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    107
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1026    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    108CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1026    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    109PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1028    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    110PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1029    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    111PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1029    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    112CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1032    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    113
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1032    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    114CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1032    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    115PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1034    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    116PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1035    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    117PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1035    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    118CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1038    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    119
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1038    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    120CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1038    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    121PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1040    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    122PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1041    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    123PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1041    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    124CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1044    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    125
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1044    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    126CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1044    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    127PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1046    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    128PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1047    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    129PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1047    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    130CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1050    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    131
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1050    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    132CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1050    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    133PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1052    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    134PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1053    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    135PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1053    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    136CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1056    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    137
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1056    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    138CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1056    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    139PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1058    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    140PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1059    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    141PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1059    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    142CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1062    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    143
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1062    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    144CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1062    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    145PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PKC
    Pathway No. : 1064    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    146PLA2-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1065    		1
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    147PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• PLA2
    Pathway No. : 1065    		6
    (uM^-1 s^-1)    		0.1
    (s^-1)    		Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    148CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1068    		72.0006
    (uM^-2 s^-1)    		72
    (s^-1)    		Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    149
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1068    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    150CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• CaM
    Pathway No. : 1068    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    Ca acting as a Product in a reaction in      Ajay_Bhalla_2007_ReacDiff3 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff3
    Pathway No. : 918
    		• 2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    2Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics
    Pathway No. : 926    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    3Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[1]
    Pathway No. : 931    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    4Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[2]
    Pathway No. : 937    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    5Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[3]
    Pathway No. : 943    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    6Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[4]
    Pathway No. : 949    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    7Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[5]
    Pathway No. : 955    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    8Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[6]
    Pathway No. : 962    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    9Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[7]
    Pathway No. : 968    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    10Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[8]
    Pathway No. : 975    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    11Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[9]
    Pathway No. : 980    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    12Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[10]
    Pathway No. : 986    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    13Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[11]
    Pathway No. : 992    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    14Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[12]
    Pathway No. : 998    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    15Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[13]
    Pathway No. : 1003    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    16Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[14]
    Pathway No. : 1009    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    17Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[15]
    Pathway No. : 1015    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    18Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[16]
    Pathway No. : 1020    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    19Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[17]
    Pathway No. : 1027    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    20Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[18]
    Pathway No. : 1033    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    21Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[19]
    Pathway No. : 1039    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    22Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[20]
    Pathway No. : 1045    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    23Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[21]
    Pathway No. : 1051    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    24Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[22]
    Pathway No. : 1057    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca
    25Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff3
    Accession No. : 84
    		• kinetics[23]
    Pathway No. : 1063    		2
    (s^-1)    		2
    (s^-1)    		Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca


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