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Reaction List for pathway CaM (Pathway Number 954) in Accession Ajay_Bhalla_2007_ReacDiff3 (Accession Number 84) | Entries are grouped according to Pathway Number and they are alternately color coded using  and  color.
Further ordering can be done to the table header.   indicates that ordering is done according to ascending or descending order.
Keq is calculated only for first order reactions.
Kd is calculated only for second order reactions. [nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules] |
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Reaction
Name | Pathway Name /
Pathway No. | Kf | Kb | Kd | tau | Reagents | | 1 | CaM-TR2-bind-Ca | CaM
Pathway No. 954 | 72.0006
(uM^-2 s^-1) | 72
(s^-1) | Kd(af) = 1(uM) | - | Substrate:
Ca
Ca
CaM
Products:
CaM-TR2-Ca2
| | | Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !).... | | 2 | CaM-TR2-Ca2-bind
-Ca | CaM
Pathway No. 954 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate:
Ca
CaM-TR2-Ca2
Products:
CaM-Ca3
| | | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 | | 3 | CaM-Ca3-bind-Ca | CaM
Pathway No. 954 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5051(uM) | - | Substrate:
Ca
CaM-Ca3
Products:
CaM-Ca4
| | | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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