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Molecule Parameter List for cAMP.R2C2 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | Statistics | Accession and Pathway Details | |
cAMP.R2C2 acting as a Molecule in cAMP_pathway Network
Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered | cAMP.R2C2 | cAMP_pathway Accession No. : 25 | PKA Pathway No. : 135 | 0 | 1000 | No | CoInit was .0624 |
cAMP.R2C2 acting as a Substrate in a reaction in cAMP_pathway Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | cAMP-bind-site-B 2 | cAMP_pathway Accession No. : 25 | PKA Pathway No. : 135 | 54 (uM^-1 s^-1) | 33 (s^-1) | Kd(bf) = 0.6111(uM) | - | Substrate cAMP cAMP.R2C2
Product cAMP2.R2C2
| For now let us set this to the same Km (1e-7M) as site B. This gives kf/kb = .7e-7M * 1e6 / (6e5^2) : 1/(6e5^2) = 2e-13:2.77e-12 Smith et al have better values. They say that this is cooperative, so the consts are now kf/kb =8.3e-4 |
cAMP.R2C2 acting as a Product in a reaction in cAMP_pathway Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | cAMP-bind-site-B 1 | cAMP_pathway Accession No. : 25 | PKA Pathway No. : 135 | 54 (uM^-1 s^-1) | 33 (s^-1) | Kd(bf) = 0.6111(uM) | - | Substrate R2C2 cAMP
Product cAMP.R2C2
| Hasler et al FASEB J 6:2734-2741 1992 say Kd =1e-7M for type II, 5.6e-8 M for type I. Take mean which comes to 2e-13 #/cell Smith et al PNAS USA 78:3 1591-1595 1981 have better data. First kf/kb=2.1e7/M = 3.5e-5 (#/cell). Ogreid and Doskeland Febs Lett 129:2 287-292 1981 have figs suggesting time course of complete assoc is < 1 min. |
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