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Molecule Parameter List for PKA-inhibitor

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
PKA-inhibitor participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000010

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • MAPK_network_
    2003
  • 50Network
    Shared_Object_MAPK_network_2003 PKC PLA2 
    PLCbeta Gq MAPK 
    Ras EGFR Sos 
    PLC_g CaMKII CaM 
    PP1 PP2B PKA 
    AC 
    This is a network model of many pathways present at the neuronal synapse. The network has properties of temporal tuning as well as steady-state computational properties. In its default form the network is bistable.Bhalla US Biophys J. 2004 Aug;87(2):745-53

    PKA-inhibitor acting as a Molecule in  
    MAPK_network_2003 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    PKA-inhibitor
  • MAPK_network_
    2003

    Accession No. : 50
  • PKA
    Pathway No. : 220
    0.251000No
    About 25% of PKA C subunit is dissociated in resting cells without having any noticable activity. Doskeland and Ogreid Int J biochem 13 pp1-19 suggest that this is because there is a corresponding amount of inhibitor protein.

    PKA-inhibitor acting as a Substrate in a reaction in  
    MAPK_network_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    inhib-PKA
  • MAPK_network_
    2003

    Accession No. : 50
  • PKA
    Pathway No. : 220
    60
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 0.0167(uM)-Substrate
    PKA-active
    PKA-inhibitor

    Product
    inhibited-PKA
    This has to be set to zero for matching the expts in vitro. In vivo we need to consider the inhibition though. kf = 1e-5 kb = 1



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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