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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000021

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
CaMKII_200349Network
Shared_Object_CaMKII_2003,  CaMKII,  CaM,  
PP1,  PP2B 
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal.
Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaM-Ca3 acting as a Molecule in  CaMKII_2003 Network
NameAccession NamePathway NameInitial Conc.
(uM)		Volume
(fL)		Buffered
CaM-Ca3CaMKII_2003
Accession No. : 49
  • Shared_Object_
    CaMKII_2003
    Pathway No. : 201
    		• 01000No

    CaM-Ca3 acting as a Substrate in a reaction in      CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1CaM-Ca3-bind-CaCaMKII_2003
    Accession No. : 49    		CaM
    Pathway No. : 203    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5054(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    2
  • CaMCa3-bind-CaNA
    B
    		• CaMKII_2003
    Accession No. : 49    		PP2B
    Pathway No. : 205    		2.238
    (uM^-1 s^-1)    		1
    (s^-1)    		Kd(bf) = 0.4468(uM)-Substrate
    CaM-Ca3
    CaNAB-Ca4

    Product
    CaMCa3-CaNAB

    CaM-Ca3 acting as a Product in a reaction in      CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
  • CaM-TR2-Ca2-bind
    -Ca
    		• CaMKII_2003
    Accession No. : 49    		CaM
    Pathway No. : 203    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
    K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10


    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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