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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | Statistics | Accession and Pathway Details | |
CaM-Ca3 acting as a Molecule in Ajay_Bhalla_2007_PKM Network
Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered | CaM-Ca3 | Ajay_Bhalla_ 2007_PKM Accession No. : 80 | CaM Pathway No. : 373 | 0 | 1.5 | No |
CaM-Ca3 acting as a Substrate in a reaction in Ajay_Bhalla_2007_PKM Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-Ca3-bind-Ca | Ajay_Bhalla_ 2007_PKM Accession No. : 80 | CaM Pathway No. : 373 | 0.465 (uM^-1 s^-1) | 10 (s^-1) | Kd(bf) = 21.5053(uM) | - | Substrate Ca CaM-Ca3
Product CaM-Ca4
| Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in Ajay_Bhalla_2007_PKM Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-Ca2-bind-Ca | Ajay_Bhalla_ 2007_PKM Accession No. : 80 | CaM Pathway No. : 373 | 3.6 (uM^-1 s^-1) | 10 (s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate Ca CaM-Ca2
Product CaM-Ca3
| K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details. |
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