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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000011

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_PKM
  • 80Network
    Shared_Object_Ajay_Bhalla_2007_PKM PKC MAPK 
    Ras CaM PKM 
    This is a non-bistable model of ERKII signaling that also incorporates PKM synthesis triggered by Ca influx. It is a simplified variant of the model of Ajay SM, Bhalla US. Eur J Neurosci. 2004 Nov;20(10):2671-80.

    CaM-Ca3 acting as a Molecule in  
    Ajay_Bhalla_2007_PKM Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CaM-Ca3
  • Ajay_Bhalla_
    2007_PKM

    Accession No. : 80
  • CaM
    Pathway No. : 373
    01.5No

    CaM-Ca3 acting as a Substrate in a reaction in  
    Ajay_Bhalla_2007_PKM Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_PKM

    Accession No. : 80
  • CaM
    Pathway No. : 373
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5053(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
    Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    CaM-Ca3 acting as a Product in a reaction in  
    Ajay_Bhalla_2007_PKM Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_PKM

    Accession No. : 80
  • CaM
    Pathway No. : 373
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
    K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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