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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | | CaMKIII | 90 | Network |
Shared_Object_CaMKIII, CaM | | CaMKIII is activated by Ca2+ and inactivated by S6K. Since CaMKIII inhibits eEF2, the net effect of Ca2+ on elongation is inhibitory and of S6K is excitatory |
CaM-Ca3 acting as a Molecule in CaMKIII Network
| Name | Accession Name | Pathway Name | Initial Conc.
(uM) | Volume
(fL) | Buffered | | CaM-Ca3 | CaMKIII
Accession No. : 90 | CaM
Pathway No. : 1094 | 0 | 1000 | No |
CaM-Ca3 acting as a Substrate in a reaction in CaMKIII Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca3-bind-Ca | CaMKIII
Accession No. : 90 | CaM
Pathway No. : 1094 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5051(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in CaMKIII Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca2-bind-Ca | CaMKIII
Accession No. : 90 | CaM
Pathway No. : 1094 | 3.6001
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7777(uM) | - | Substrate
Ca
CaM-Ca2
Product
CaM-Ca3
| | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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