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Molecule Parameter List for CaM-TR2-Ca2

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-TR2-Ca2 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000021

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • MAPK_network_
    2003
  • 50Network
    Shared_Object_MAPK_network_2003 PKC PLA2 
    PLCbeta Gq MAPK 
    Ras EGFR Sos 
    PLC_g CaMKII CaM 
    PP1 PP2B PKA 
    AC 
    This is a network model of many pathways present at the neuronal synapse. The network has properties of temporal tuning as well as steady-state computational properties. In its default form the network is bistable.Bhalla US Biophys J. 2004 Aug;87(2):745-53

    CaM-TR2-Ca2 acting as a Molecule in  
    MAPK_network_2003 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CaM-TR2-Ca2
  • MAPK_network_
    2003

    Accession No. : 50
  • Shared_Object_
    MAPK_network_
    2003

    Pathway No. : 206
  • 01000No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.

    CaM-TR2-Ca2 acting as a Substrate in a reaction in  
    MAPK_network_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1
  • CaM-TR2-Ca2-bind
    -Ca
  • MAPK_network_
    2003

    Accession No. : 50
  • CaM
    Pathway No. : 217
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    2
  • CaM-Ca2-bind-CaN
    AB
  • MAPK_network_
    2003

    Accession No. : 50
  • PP2B
    Pathway No. : 219
    0.24
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 4.1667(uM)-Substrate
    CaM-TR2-Ca2
    CaNAB-Ca4

    Product
    CaMCa2-CANAB
      Disabled. See notes for PP2B7.g

    CaM-TR2-Ca2 acting as a Product in a reaction in  
    MAPK_network_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    CaM-TR2-bind-Ca
  • MAPK_network_
    2003

    Accession No. : 50
  • CaM
    Pathway No. : 217
    72
    (uM^-2 s^-1)
    72
    (s^-1)
    Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
    Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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