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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | NonOsc_Ca_
IP3metabolism | 23 | Network |
MIPP, CaMKII, CaM,
PKC, IP3-3K, CaRegulation,
Gq, PLCbeta, 134_dephos,
145_dephos, IP4-system, IHP-system,
1345_dephos | | This network models detailed metabolism of Ins(145)P3, integrated with GPCR mediated PLCbeta activation and Ca release by the InsP3 receptor in the neuron. The calcium response is non-oscillatory. Mishra J, Bhalla US. Biophys J. 2002 Sep;83(3):1298-316. |
CaM-Ca3 acting as a Molecule in NonOsc_Ca_IP3metabolism Network
| Name | Accession Name | Pathway Name | Initial Conc.
(uM) | Volume
(fL) | Buffered | | CaM-Ca3 | NonOsc_Ca_
IP3metabolism
Accession No. : 23 | CaM
Pathway No. : 107 | 0 | 1000 | No | | The TR1 end now begins to bind Ca. This form has 2 Ca's on the TR2 end, and one on the TR1. |
CaM-Ca3 acting as a Substrate in a reaction in NonOsc_Ca_IP3metabolism Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca3-bind-Ca | NonOsc_Ca_
IP3metabolism
Accession No. : 23 | CaM
Pathway No. : 107 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | Use K3 = 21.5 uM here from Stemmer and Klee table 3. Stemmer and Klee 1994 Biochem 33:6859-6866 kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in NonOsc_Ca_IP3metabolism Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-TR2-Ca2-bind
-Ca | NonOsc_Ca_
IP3metabolism
Accession No. : 23 | CaM
Pathway No. : 107 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate
Ca
CaM-TR2-Ca2
Product
CaM-Ca3
| | Stemmer and Klee 1994 Biochem 33:6859-6866 K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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