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Molecule Parameter List for CaNAB-Ca2

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaNAB-Ca2 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000011

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
CaMKII_200349Network
Shared_Object_CaMKII_2003,  CaMKII,  CaM,  
PP1,  PP2B 
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal.
Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaNAB-Ca2 acting as a Molecule in  CaMKII_2003 Network
NameAccession NamePathway NameInitial Conc.
(uM)		Volume
(fL)		Buffered
CaNAB-Ca2CaMKII_2003
Accession No. : 49		PP2B
Pathway No. : 205		01000No

CaNAB-Ca2 acting as a Substrate in a reaction in  CaMKII_2003 Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
NameAccession NamePathway NameKfKbKdtauReagents
  • Ca-bind-CaNAB-Ca
    2
    		• CaMKII_2003
    Accession No. : 49    		PP2B
    Pathway No. : 205    		3.6
    (uM^-2 s^-1)    		1
    (s^-1)    		Kd(af) = 0.527(uM)-Substrate
    Ca
    Ca
    CaNAB-Ca2

    Product
    CaNAB-Ca4
    This process is probably much more complicated and involves CaM. However, as I can't find detailed info I am bundling this into a single step. Based on Steemer and Klee pg 6863, the Kact is 0.5 uM. kf/kb = 1/(0.5 * 6e5)^2 = 1.11e-11

    CaNAB-Ca2 acting as a Product in a reaction in      CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    Ca-bind-CaNABCaMKII_2003
    Accession No. : 49    		PP2B
    Pathway No. : 205    		10008
    (uM^-2 s^-1)    		1
    (s^-1)    		Kd(af) = 0.01(uM)-Substrate
    Ca
    Ca
    CaNAB

    Product
    CaNAB-Ca2
    going on the experience with CaM, we put the fast (high affinity) sites first. We only know (Stemmer and Klee) that the affinity is < 70 nM. Assuming 10 nM at first, we get kf = 2.78e-8, kb = 1. Try 20 nM. kf = 7e-9, kb = 1 


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