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Molecule Parameter List for Rec-Gq

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color.

Statistics

Rec-Gq participated as	Molecule	Sum total of	Enzyme	Substrate of an enzyme	Product of an enzyme	Substrate in Reaction	Product in Reaction
No. of occurrences	1	0	0	0	0	2	1

Accession and Pathway Details

Accession Name	Accession No.	Accession Type	Pathway Link
MAPK_network_ 2003	50	Network	Shared_Object_MAPK_network_2003,  PKC,  PLA2,   PLCbeta,  Gq,  MAPK,   Ras,  EGFR,  Sos,   PLC_g,  CaMKII,  CaM,   PP1,  PP2B,  PKA,   AC
This is a network model of many pathways present at the neuronal synapse. The network has properties of temporal tuning as well as steady-state computational properties. In its default form the network is bistable.Bhalla US Biophys J. 2004 Aug;87(2):745-53

Rec-Gq acting as a Molecule in  MAPK_network_2003 Network

Name	Accession Name	Pathway Name	Initial Conc. (uM)	Volume (fL)	Buffered
Rec-Gq	MAPK_network_ 2003 Accession No. : 50	Gq Pathway No. : 210	0	1000	No
Fraction of Rec-Gq is 44% of rec, from Fay et al. Since this is not the same receptor, this value is a bit doubtful. Still, we adjust the rate consts in Rec-bind-Gq to match.

Rec-Gq acting as a Substrate in a reaction in  MAPK_network_2003 Network

Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.

	Name	Accession Name	Pathway Name	Kf	Kb	Kd	tau	Reagents
1	Glu-bind-Rec-Gq	MAPK_network_ 2003 Accession No. : 50	Gq Pathway No. : 210	16.8 (uM^-1 s^-1)	0.1 (s^-1)	Kd(bf) = 0.006(uM)	-	Substrate Glu Rec-Gq Product Rec-Glu-Gq
	From Fay et al kb3 = kb = 1.06e-3 which is rather slow. k+1 = kf = 2.8e7 /M/sec= 4.67e-5/sec use 5e-5. However, the Kd from Martin et al may be more appropriate, as this is Glu not the system from Fay. kf = 2.8e-5, kb = 10 Let us compromise. since we have the Fay model, keep kf = k+1 = 2.8e-5. But kb (k-3) is .01 * k-1 from Fay. Scaling by .01, kb = .01 * 10 = 0.1
2	Antag-bind-Rec-G q	MAPK_network_ 2003 Accession No. : 50	Gq Pathway No. : 210	60 (uM^-1 s^-1)	0.01 (s^-1)	Kd(bf) = 0.0002(uM)	-	Substrate Rec-Gq mGluRAntag Product Blocked-rec-Gq
	The rate consts give a total binding affinity of only

Rec-Gq acting as a Product in a reaction in  MAPK_network_2003 Network

Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.

Name	Accession Name	Pathway Name	Kf	Kb	Kd	tau	Reagents
Rec-bind-Gq	MAPK_network_ 2003 Accession No. : 50	Gq Pathway No. : 210	0.6 (uM^-1 s^-1)	1 (s^-1)	Kd(bf) = 1.6667(uM)	-	Substrate G-GDP mGluR Product Rec-Gq
Lets try out the same kinetics as the Rec-Glu-bind-Gq This is much too forward. We know that the steady-state amount of Rec-Gq should be 40% of the total amount of receptor. This is for a different receptor, still we can try to match the value. kf = 1e-6 and kb = 1 give 0.333:0.8 which is pretty close.