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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | CaMKII_noPKA_
model3 | 62 | Network |
Shared_Object_CaMKII_noPKA_model3, CaMKII, CaM,
PP1, PP2B, PP1_PSD | | This is the model of CaMKII bistability, model 3. It exhibits bistability in CaMKII activation due to autophosphorylation at the PSD and local saturation of PP1. This version of model 3 does not include the full PKA regulatory pathway, and instead has a predefined initial amount of active PKA. |
CaM-Ca3 acting as a Molecule in CaMKII_noPKA_model3 Network
CaM-Ca3 acting as a Substrate in a reaction in CaMKII_noPKA_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca3-bind-Ca | CaMKII_noPKA_
model3
Accession No. : 62 | Shared_Object_
CaMKII_noPKA_
model3
Pathway No. : 257 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in CaMKII_noPKA_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-TR2-Ca2-bind
-Ca | CaMKII_noPKA_
model3
Accession No. : 62 | CaM
Pathway No. : 259 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate
Ca
CaM-TR2-Ca2
Product
CaM-Ca3
| | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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