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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000011

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_Bistable
  • 79Network
    Shared_Object_Ajay_Bhalla_2007_Bistable PKC PLA2 
    MAPK Ras CaM 
    This is a model of ERKII signaling which is bistable due to feedback. The feedback occurs through ERKII phosphorylation of phospholipase A2 (PLA2), leading to increased production of arachidonic acid (AA), which activates protein kinase C (PKC) which activates c-Raf which is upstream of ERKII.
    The model is a highly simplified variant of more detailed bistable models of MAPK signaling (Bhalla US, Iyengar R. Science. 1999 Jan 15;283(5400):381-7, Ajay SM, Bhalla US. Eur J Neurosci. 2004 Nov;20(10):2671-80)

    CaM-Ca3 acting as a Molecule in  
    Ajay_Bhalla_2007_Bistable Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CaM-Ca3
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    0125.7No

    CaM-Ca3 acting as a Substrate in a reaction in  
    Ajay_Bhalla_2007_Bistable Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5053(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
    Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    CaM-Ca3 acting as a Product in a reaction in  
    Ajay_Bhalla_2007_Bistable Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
    K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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