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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000011

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
mTOR_pathway92Network
Shared_Object_mTOR_pathway AKT_mod S6Kinase 
PI3K_mod TrKB_mod mTOR_model 
MAPK PKC 4E-BP_mod 
Ras Sos 43S_complex 
CaM 
This model consists of various sub-modules. They are as follows: 1) BDNF receptor signaling 2) AKT signaling 3) 4E-BP model 4) S6 Kinase model 5) CaMKIII model 6) Protein synthesis model 7) CaM 8) PKC 9) MAPK model.

CaM-Ca3 acting as a Molecule in  
mTOR_pathway Network
NameAccession NamePathway NameInitial Conc.
(uM)
Volume
(fL)
Buffered
CaM-Ca3mTOR_pathway
Accession No. : 92
CaM
Pathway No. : 1109
01000No

CaM-Ca3 acting as a Substrate in a reaction in  
mTOR_pathway Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
NameAccession NamePathway NameKfKbKdtauReagents
CaM-Ca3-bind-CamTOR_pathway
Accession No. : 92
CaM
Pathway No. : 1109
0.465
(uM^-1 s^-1)
10
(s^-1)
Kd(bf) = 21.5051(uM)-Substrate
Ca
CaM-Ca3

Product
CaM-Ca4
Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

CaM-Ca3 acting as a Product in a reaction in  
mTOR_pathway Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
NameAccession NamePathway NameKfKbKdtauReagents
CaM-Ca2-bind-CamTOR_pathway
Accession No. : 92
CaM
Pathway No. : 1109
3.6001
(uM^-1 s^-1)
10
(s^-1)
Kd(bf) = 2.7777(uM)-Substrate
Ca
CaM-Ca2

Product
CaM-Ca3
K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10