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Molecule Parameter List for CaM_dash_Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | Statistics | Accession and Pathway Details | |
Accession Name | Accession No. | Accession Type | Pathway Link | CaMKIV_submodel | 93 | Network | kinetics, compartment_1 | Calcium-calmodulin dependent protein kinase IV (CaMKIV) pathway is one of the sub-model in signaling cascade regulating mRNA synthesis |
CaM_dash_Ca3 acting as a Molecule in CaMKIV_submodel Network
Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered | CaM_dash_Ca3 | CaMKIV_submodel Accession No. : 93 | kinetics Pathway No. : 1110 | 0 | 1000 | No | |
CaM_dash_Ca3 acting as a Substrate in a reaction in CaMKIV_submodel Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM_dash_Ca3_ dash_bind_dash_ Ca | CaMKIV_submodel Accession No. : 93 | kinetics Pathway No. : 1110 | 0.465 (uM^-1 s^-1) | 10 (s^-1) | Kd(bf) = 21.5051(uM) | - | Substrate Ca CaM_dash_Ca3
Product CaM_dash_Ca4
| Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM_dash_Ca3 acting as a Product in a reaction in CaMKIV_submodel Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM_dash_Ca2_ dash_bind_dash_ Ca | CaMKIV_submodel Accession No. : 93 | kinetics Pathway No. : 1110 | 3.6001 (uM^-1 s^-1) | 10 (s^-1) | Kd(bf) = 2.7777(uM) | - | Substrate Ca CaM_dash_Ca2
Product CaM_dash_Ca3
| K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details. |
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