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Molecule Parameter List for Ca

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Ca participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences40000023979

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_ReacDiff2
  • 83NetworkShared_Object_Ajay_Bhalla_2007_ReacDiff PKC MAPK 
    Ras CaM PKM chain kinetics PKC MAPK Ras CaM PKM kinetics[1] 
    PKC MAPK Ras kinetics[3] CaM PKM kinetics[2] PKC MAPK Ras 
    CaM PKM PKC MAPK Ras CaM PKM kinetics[4] PKC MAPK Ras CaM 
    PKM kinetics[5] PKC MAPK Ras CaM PKM kinetics[6] PKC MAPK 
    Ras CaM PKM kinetics[7] PKC MAPK Ras CaM PKM kinetics[8] 
    PKC MAPK Ras CaM PKM kinetics[9] PKC MAPK Ras CaM PKM kinetics[10] 
    PKC MAPK Ras CaM PKM kinetics[11] PKC MAPK Ras CaM PKM kinetics[12] 
    PKC MAPK Ras CaM PKM kinetics[13] PKC MAPK Ras CaM PKM kinetics[14] 
    PKC MAPK Ras CaM PKM kinetics[15] PKC MAPK Ras CaM PKM kinetics[16] 
    PKC MAPK Ras CaM PKM kinetics[17] PKC MAPK Ras CaM PKM kinetics[18] 
    PKC MAPK Ras CaM PKM kinetics[19] PKC MAPK Ras CaM PKM kinetics[20] 
    PKC MAPK Ras CaM PKM kinetics[21] PKC MAPK Ras CaM PKM kinetics[22] 
    PKC MAPK Ras CaM PKM kinetics[23] PKC MAPK Ras CaM PKM kinetics[24] 
    PKC MAPK Ras CaM PKM kinetics[25] PKC MAPK Ras CaM PKM kinetics[26] 
    PKC MAPK Ras CaM PKM kinetics[27] PKC MAPK Ras CaM PKM kinetics[28] 
    PKC MAPK Ras CaM PKM kinetics[29] PKC MAPK Ras CaM PKM kinetics[30] 
    PKC MAPK Ras CaM PKM kinetics[31] PKC MAPK Ras CaM PKM kinetics[32] 
    PKC MAPK Ras CaM PKM kinetics[33] PKC MAPK Ras CaM PKM kinetics[34] 
    PKC MAPK Ras CaM PKM kinetics[35] PKC MAPK Ras CaM PKM kinetics[36] 
    PKC MAPK Ras CaM PKM kinetics[37] PKC MAPK Ras CaM PKM kinetics[38] 
    PKC MAPK Ras CaM PKM 
    This is a 40-compartment reaction-diffusion-transport version of the Ajay_Bhalla_2007_PKM model. The original single-compartment model is repeated 40 times. In addition, a subset (27 out of 42) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. For D = 1e-12 m^2/sec (i.e., 1 micron^2/sec ) the kf and kb of this reaction for these 10 micron compartments are both 0.01/sec In addition, we have a forward (dendrite to soma) transport term of 1 microns/sec. This converts to a rate of 0.1/sec, but applies only to the kf. So the total kf of the diffusion 'reaction' is 0.11 for D = 1 micron^2/sec, and kb is 0.01. If D=0.1 micron^2/sec then kf = 0.101 and kb = 0.001. In addition this model has all molecules buffered in the first and last compartments. This boundary conditions says that the molecules are not drained out of the first compartment, nor do they all pile up in the last one.
    The stimulus file pkm_mapk22_transp_endbuf_D1e-13_Fig4CD which was used for the model to replicate Figure 4C and 4D from the paper.

    Ca acting as a Molecule in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics
    Pathway No. : 684
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[1]
    Pathway No. : 690
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[2]
    Pathway No. : 697
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[3]
    Pathway No. : 694
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[4]
    Pathway No. : 708
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[5]
    Pathway No. : 714
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[6]
    Pathway No. : 720
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[7]
    Pathway No. : 726
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[8]
    Pathway No. : 732
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[9]
    Pathway No. : 738
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[10]
    Pathway No. : 744
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[11]
    Pathway No. : 750
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[12]
    Pathway No. : 756
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[13]
    Pathway No. : 762
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[14]
    Pathway No. : 768
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[15]
    Pathway No. : 774
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[16]
    Pathway No. : 780
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[17]
    Pathway No. : 786
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[18]
    Pathway No. : 792
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[19]
    Pathway No. : 798
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[20]
    Pathway No. : 804
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[21]
    Pathway No. : 810
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[22]
    Pathway No. : 816
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[23]
    Pathway No. : 822
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[24]
    Pathway No. : 828
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[25]
    Pathway No. : 834
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[26]
    Pathway No. : 840
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[27]
    Pathway No. : 846
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[28]
    Pathway No. : 852
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[29]
    Pathway No. : 858
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[30]
    Pathway No. : 864
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[31]
    Pathway No. : 870
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[32]
    Pathway No. : 876
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[33]
    Pathway No. : 882
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[34]
    Pathway No. : 888
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[35]
    Pathway No. : 894
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[36]
    Pathway No. : 900
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[37]
    Pathway No. : 906
    0.081.5No
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.081.5Yes
    Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[38]
    Pathway No. : 912
    0.081.5Yes

    Ca acting as a Substrate in a reaction in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 678
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    2CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    3CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    4CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    6diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    7PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 685
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    8CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    9CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    10CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    11CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    12diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    13PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 703
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    14PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 691
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    15CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    16CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    17CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    18CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    19diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    20PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 698
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    21CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    22CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    23CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    24CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    25diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    26PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 727
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    27CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    28CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    29CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    30CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    31diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    32PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 709
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    33CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    34CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    35CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    36CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    37diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    38PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 715
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    39CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    40CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    41CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    42CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    43diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    44PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 721
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    45CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    46CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    47CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    48CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    49diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    50PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 775
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    51CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    52CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    53CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    54CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    55diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    56PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 733
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    57CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    58CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    59CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    60CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    61diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    62PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 739
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    63CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    64CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    65CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    66CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    67diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    68PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 745
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    69CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    70CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    71CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    72CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    73diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    74PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 751
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    75CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    76CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    77CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    78CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    79diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    80PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 757
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    81CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    82CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    83CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    84CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    85diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    86PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 763
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    87CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    88CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    89CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    90CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    91diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    92PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 769
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    93CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    94CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    95CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    96CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    97diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    98PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 871
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    99CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    100CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    101CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    102CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    103diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    104PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 781
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    105CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    106CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    107CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    108CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    109diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    110PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 787
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    111CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    112CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    113CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    114CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    115diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    116PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 793
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    117CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    118CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    119CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    120CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    121diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    122PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 799
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    123CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    124CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    125CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    126CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    127diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    128PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 805
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    129CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    130CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    131CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    132CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    133diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    134PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 811
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    135CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    136CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    137CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    138CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    139diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    140PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 817
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    141CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    142CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    143CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    144CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    145diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    146PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 823
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    147CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    148CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    149CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    150CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    151diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    152PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 829
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    153CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    154CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    155CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    156CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    157diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    158PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 835
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    159CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    160CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    161CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    162CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    163diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    164PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 841
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    165CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    166CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    167CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    168CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    169diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    170PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 847
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    171CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    172CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    173CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    174CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    175diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    176PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 853
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    177CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    178CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    179CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    180CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    181diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    182PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 859
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    183CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    184CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    185CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    186CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    187diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    188PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 865
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    189CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    190CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    191CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    192CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    193diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    194CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    195CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    196CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    197CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    198diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    199PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 877
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    200CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    201CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    202CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    203CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    204diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    205PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 883
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    206CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    207CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    208CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    209CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    210diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    211PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 889
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    212CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    213CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    214CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    215CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    216diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    217PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 895
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    218CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    219CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    220CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    221CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    222diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    223PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 901
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    224CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    225CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    226CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    227CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    228diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    229PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 907
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    230CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    231CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    232CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    233CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    234diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    235PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • PKC
    Pathway No. : 913
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    236CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    237CaM-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    238CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    239CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853

    Ca acting as a Product in a reaction in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    2Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    3diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    4Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics
    Pathway No. : 684
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    5diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    6Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[1]
    Pathway No. : 690
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    7diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    8Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[2]
    Pathway No. : 697
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    9diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    10Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[3]
    Pathway No. : 694
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    11diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    12Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[4]
    Pathway No. : 708
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    13diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    14Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[5]
    Pathway No. : 714
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    15diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    16Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[6]
    Pathway No. : 720
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    17diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    18Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[7]
    Pathway No. : 726
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    19diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    20Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[8]
    Pathway No. : 732
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    21diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    22Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[9]
    Pathway No. : 738
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    23diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    24Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[10]
    Pathway No. : 744
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    25diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    26Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[11]
    Pathway No. : 750
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    27diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    28Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[12]
    Pathway No. : 756
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    29diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    30Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[13]
    Pathway No. : 762
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    31diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    32Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[14]
    Pathway No. : 768
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    33diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    34Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[15]
    Pathway No. : 774
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    35diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    36Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[16]
    Pathway No. : 780
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    37diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    38Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[17]
    Pathway No. : 786
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    39diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    40Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[18]
    Pathway No. : 792
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    41diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    42Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[19]
    Pathway No. : 798
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    43diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    44Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[20]
    Pathway No. : 804
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    45diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    46Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[21]
    Pathway No. : 810
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    47diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    48Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[22]
    Pathway No. : 816
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    49diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    50Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[23]
    Pathway No. : 822
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    51diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    52Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[24]
    Pathway No. : 828
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    53diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    54Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[25]
    Pathway No. : 834
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    55diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    56Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[26]
    Pathway No. : 840
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    57diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    58Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[27]
    Pathway No. : 846
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    59diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    60Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[28]
    Pathway No. : 852
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    61diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    62Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[29]
    Pathway No. : 858
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    63diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    64Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[30]
    Pathway No. : 864
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    65diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    66Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[31]
    Pathway No. : 870
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    67diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    68Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[32]
    Pathway No. : 876
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    69diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    70Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[33]
    Pathway No. : 882
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    71diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    72Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[34]
    Pathway No. : 888
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    73diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    74Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[35]
    Pathway No. : 894
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    75diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    76Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[36]
    Pathway No. : 900
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    77diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    Ca

    Product
    Ca
    78Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[37]
    Pathway No. : 906
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca
    79Ca_diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • kinetics[38]
    Pathway No. : 912
    5
    (s^-1)
    5
    (s^-1)
    Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca



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