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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences4000007979

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_ReacDiff2
  • 83NetworkShared_Object_Ajay_Bhalla_2007_ReacDiff PKC MAPK 
    Ras CaM PKM chain kinetics PKC MAPK Ras CaM PKM kinetics[1] 
    PKC MAPK Ras kinetics[3] CaM PKM kinetics[2] PKC MAPK Ras 
    CaM PKM PKC MAPK Ras CaM PKM kinetics[4] PKC MAPK Ras CaM 
    PKM kinetics[5] PKC MAPK Ras CaM PKM kinetics[6] PKC MAPK 
    Ras CaM PKM kinetics[7] PKC MAPK Ras CaM PKM kinetics[8] 
    PKC MAPK Ras CaM PKM kinetics[9] PKC MAPK Ras CaM PKM kinetics[10] 
    PKC MAPK Ras CaM PKM kinetics[11] PKC MAPK Ras CaM PKM kinetics[12] 
    PKC MAPK Ras CaM PKM kinetics[13] PKC MAPK Ras CaM PKM kinetics[14] 
    PKC MAPK Ras CaM PKM kinetics[15] PKC MAPK Ras CaM PKM kinetics[16] 
    PKC MAPK Ras CaM PKM kinetics[17] PKC MAPK Ras CaM PKM kinetics[18] 
    PKC MAPK Ras CaM PKM kinetics[19] PKC MAPK Ras CaM PKM kinetics[20] 
    PKC MAPK Ras CaM PKM kinetics[21] PKC MAPK Ras CaM PKM kinetics[22] 
    PKC MAPK Ras CaM PKM kinetics[23] PKC MAPK Ras CaM PKM kinetics[24] 
    PKC MAPK Ras CaM PKM kinetics[25] PKC MAPK Ras CaM PKM kinetics[26] 
    PKC MAPK Ras CaM PKM kinetics[27] PKC MAPK Ras CaM PKM kinetics[28] 
    PKC MAPK Ras CaM PKM kinetics[29] PKC MAPK Ras CaM PKM kinetics[30] 
    PKC MAPK Ras CaM PKM kinetics[31] PKC MAPK Ras CaM PKM kinetics[32] 
    PKC MAPK Ras CaM PKM kinetics[33] PKC MAPK Ras CaM PKM kinetics[34] 
    PKC MAPK Ras CaM PKM kinetics[35] PKC MAPK Ras CaM PKM kinetics[36] 
    PKC MAPK Ras CaM PKM kinetics[37] PKC MAPK Ras CaM PKM kinetics[38] 
    PKC MAPK Ras CaM PKM 
    This is a 40-compartment reaction-diffusion-transport version of the Ajay_Bhalla_2007_PKM model. The original single-compartment model is repeated 40 times. In addition, a subset (27 out of 42) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. For D = 1e-12 m^2/sec (i.e., 1 micron^2/sec ) the kf and kb of this reaction for these 10 micron compartments are both 0.01/sec In addition, we have a forward (dendrite to soma) transport term of 1 microns/sec. This converts to a rate of 0.1/sec, but applies only to the kf. So the total kf of the diffusion 'reaction' is 0.11 for D = 1 micron^2/sec, and kb is 0.01. If D=0.1 micron^2/sec then kf = 0.101 and kb = 0.001. In addition this model has all molecules buffered in the first and last compartments. This boundary conditions says that the molecules are not drained out of the first compartment, nor do they all pile up in the last one.
    The stimulus file pkm_mapk22_transp_endbuf_D1e-13_Fig4CD which was used for the model to replicate Figure 4C and 4D from the paper.

    CaM-Ca3 acting as a Molecule in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    0.00341.5No
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    0.00341.5Yes
    CaM-Ca3
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    0.00341.5Yes

    CaM-Ca3 acting as a Substrate in a reaction in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    2diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    3CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    4diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    5CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    6diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    7CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    8diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    9CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    10diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    11CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    12diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    13CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    14diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    15CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    16diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    17CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    18diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    19CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    20diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    21CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    22diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    23CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    24diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    25CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    26diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    27CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    28diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    29CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    30diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    31CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    32diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    33CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    34diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    35CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    36diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    37CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    38diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    39CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    40diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    41CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    42diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    43CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    44diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    45CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    46diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    47CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    48diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    49CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    50diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    51CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    52diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    53CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    54diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    55CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    56diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    57CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    58diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    59CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    60diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    61CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    62diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    63CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    64diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    65CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    66diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    67CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    68diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    69CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    70diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    71CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    72diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    73CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    74diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    75CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    76diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    77CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    78diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    79CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    CaM-Ca3 acting as a Product in a reaction in  
    Ajay_Bhalla_2007_ReacDiff2 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    2CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 681
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    3diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    4CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 688
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    6CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 695
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    7diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    8CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 701
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    9diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    10CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 706
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    11diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    12CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 712
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    13diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    14CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 718
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    15diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    16CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 724
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    17diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    18CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 730
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    19diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    20CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 736
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    21diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    22CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 742
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    23diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    24CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 748
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    25diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    26CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 754
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    27diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    28CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 760
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    29diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    30CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 766
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    31diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    32CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 772
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    33diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    34CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 778
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    35diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    36CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 784
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    37diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    38CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 790
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    39diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    40CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 796
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    41diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    42CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 802
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    43diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    44CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 808
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    45diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    46CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 814
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    47diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    48CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 820
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    49diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    50CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 826
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    51diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    52CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 832
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    53diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    54CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 838
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    55diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    56CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 844
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    57diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    58CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 850
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    59diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    60CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 856
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    61diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    62CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 862
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    63diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    64CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 868
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    65diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    66CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 874
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    67diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    68CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 880
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    69diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    70CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 886
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    71diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    72CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 892
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    73diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    74CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 898
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    75diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    76CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 904
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    77diff
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • Shared_Object_
    Ajay_Bhalla_
    2007_ReacDiff

    Pathway No. : 677
  • 0.101
    (s^-1)
    0.001
    (s^-1)
    Keq = 0.0099(uM)9.804secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    78CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 910
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    79CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_ReacDiff2

    Accession No. : 83
  • CaM
    Pathway No. : 916
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10



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