NCBS Home page
Accession List
Pathway List
Search
Authorized Users
Help
News archives

Enter a Search String

Special character and space not allowed in the query term. Search string should be at least 2 characters long.
Search in: Search for Match By

Molecule Parameter List for CaNAB-Ca4

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaNAB-Ca4 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1010031

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
CaMKII_200349Network
Shared_Object_CaMKII_2003 CaMKII CaM 
PP1 PP2B 
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal.
Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaNAB-Ca4 acting as a Molecule in  
CaMKII_2003 Network
NameAccession NamePathway NameInitial Conc.
(uM)
Volume
(fL)
Buffered
CaNAB-Ca4CaMKII_2003
Accession No. : 49
  • Shared_Object_
    CaMKII_2003

    Pathway No. : 201
  • 01000No

    CaNAB-Ca4 acting as an Enzyme in  
    CaMKII_2003 Network
    Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    CaNAB-Ca4 /
  • dephosph_
    inhib1_noCaM
  • CaMKII_2003
    Accession No. : 49
  • Shared_Object_
    CaMKII_2003

    Pathway No. : 201
  • 4.970760.0344explicit E-S complexSubstrate
    I1*

    Product
    I1
    The rates here are so slow I do not know if we should even bother with this enz reacn. These numbers are from Liu and Storm. Other refs suggest that the Km stays the same but the Vmax goes to 10% of the CaM stim levels. Prev: k1=2.2e-9, k2 = 0.0052, k3 = 0.0013 New : k1=5.7e-8, k2=.136, k3=.034

    CaNAB-Ca4 acting as a Substrate in a reaction in  
    CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1
  • CaM-Ca2-bind-CaN
    AB
  • CaMKII_2003
    Accession No. : 49
    PP2B
    Pathway No. : 205
    0.24
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 4.1667(uM)-Substrate
    CaM-TR2-Ca2
    CaNAB-Ca4

    Product
    CaMCa2-CANAB
      Disabled. See notes for PP2B7.g
    2
  • CaMCa3-bind-CaNA
    B
  • CaMKII_2003
    Accession No. : 49
    PP2B
    Pathway No. : 205
    2.238
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 0.4468(uM)-Substrate
    CaM-Ca3
    CaNAB-Ca4

    Product
    CaMCa3-CaNAB
    3
  • CaMCa4-bind-CaNA
    B
  • CaMKII_2003
    Accession No. : 49
    PP2B
    Pathway No. : 205
    600
    (uM^-1 s^-1)
    1
    (s^-1)
    Kd(bf) = 0.0017(uM)-Substrate
    CaM-Ca4
    CaNAB-Ca4

    Product
    CaMCa4-CaNAB

    CaNAB-Ca4 acting as a Product in a reaction in  
    CaMKII_2003 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
  • Ca-bind-CaNAB-Ca
    2
  • CaMKII_2003
    Accession No. : 49
    PP2B
    Pathway No. : 205
    3.6
    (uM^-2 s^-1)
    1
    (s^-1)
    Kd(af) = 0.527(uM)-Substrate
    Ca
    Ca
    CaNAB-Ca2

    Product
    CaNAB-Ca4
    This process is probably much more complicated and involves CaM. However, as I can't find detailed info I am bundling this into a single step. Based on Steemer and Klee pg 6863, the Kact is 0.5 uM. kf/kb = 1/(0.5 * 6e5)^2 = 1.11e-11



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
    This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details.