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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | AMPAR_traff_
model1 | 60 | Network |
Shared_Object_AMPAR_traff_model1, CaMKII, CaM,
PP1, PP2B, PP1_PSD,
PKA, AC, AMPAR,
AMPAR_memb | | This is the basic model of AMPAR trafficking bistability. It is based on Hayer and Bhalla, PLoS Comput. Biol. 2005. It includes the degradation and turnover of AMPARs. The CaMKII portion of the model is not bistable. |
CaM-Ca3 acting as a Molecule in AMPAR_traff_model1 Network
| Name | Accession Name | Pathway Name | Initial Conc.
(uM) | Volume
(fL) | Buffered | | CaM-Ca3 | AMPAR_traff_
model1
Accession No. : 60 | CaM
Pathway No. : 246 | 0 | 0.09 | No | | |
CaM-Ca3 acting as a Substrate in a reaction in AMPAR_traff_model1 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca3-bind-Ca | AMPAR_traff_
model1
Accession No. : 60 | CaM
Pathway No. : 246 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in AMPAR_traff_model1 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-TR2-Ca2-bind
-Ca | AMPAR_traff_
model1
Accession No. : 60 | CaM
Pathway No. : 246 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate
Ca
CaM-TR2-Ca2
Product
CaM-Ca3
| | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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