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Molecule Parameter List for CaM.PDE1 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | Statistics | Accession and Pathway Details | |
Accession Name | Accession No. | Accession Type | Pathway Link | AMPAR_traff_ model1 | 60 | Network | Shared_Object_AMPAR_traff_model1, CaMKII, CaM, PP1, PP2B, PP1_PSD, PKA, AC, AMPAR, AMPAR_memb | This is the basic model of AMPAR trafficking bistability. It is based on Hayer and Bhalla, PLoS Comput. Biol. 2005. It includes the degradation and turnover of AMPARs. The CaMKII portion of the model is not bistable. |
CaM.PDE1 acting as a Molecule in AMPAR_traff_model1 Network
Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered | CaM.PDE1 | AMPAR_traff_ model1 Accession No. : 60 | AC Pathway No. : 251 | 0 | 0.09 | No | Activity up 6x following Ca-CaM binding. |
CaM.PDE1 acting as an Enzyme in AMPAR_traff_model1 Network
Enzyme Molecule / Enzyme Activity | Accession Name | Pathway Name | Km (uM) | kcat (s^-1) | Ratio | Enzyme Type | Reagents | CaM.PDE1 / CaM.PDE1
| AMPAR_traff_ model1 Accession No. : 60 | AC Pathway No. : 251 | 39.6831 | 10 | 4 | explicit E-S complex | Substrate cAMP
Product AMP
| Max activity ~10umol/min/mg in presence of lots of CaM. Affinity is low, 40 uM. k3 = 10, k2 = 40, k1 = (50/40) / 6e5. |
CaM.PDE1 acting as a Product in a reaction in AMPAR_traff_model1 Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM_bind_PDE1 | AMPAR_traff_ model1 Accession No. : 60 | AC Pathway No. : 251 | 719.982 (uM^-1 s^-1) | 5 (s^-1) | Kd(bf) = 0.0069(uM) | - | Substrate CaM-Ca4 PDE1
Product CaM.PDE1
| For olf epi PDE1, affinity is 7 nM. Assume same for brain. Reaction should be pretty fast. Assume kb = 5/sec. Then kf = 5 / (0.007 * 6e5) = 1.2e-3 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details. |
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