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Molecule Parameter List for AC1 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | Statistics |
AC1 participated as | Molecule | Sum total of | Enzyme | Substrate of an enzyme | Product of an enzyme | Substrate in Reaction | Product in Reaction | No. of occurrences | 1 | 0 | 0 | 0 | 0 | 2 | 0 |
Accession and Pathway Details | |
Accession Name | Accession No. | Accession Type | Pathway Link | Ajay_Bhalla_ 2004_Feedback_ Tuning | 78 | Network | Shared_Object_Ajay_Bhalla_2004_Feedback_Tuning, PKC, PLA2, PLCbeta, Gq, MAPK, Ras, EGFR, Sos, PLC_g, CaMKII, CaM, PP1, PP2B, PKA, AC | This model is taken from Ajay SM, Bhalla US. Eur J Neurosci. 2004 Nov;20(10):2671-80. This is the feedback model from Figure 8a. |
AC1 acting as a Molecule in Ajay_Bhalla_2004_Feedback_Tuning Network
Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered | AC1 | Ajay_Bhalla_ 2004_Feedback_ Tuning Accession No. : 78 | AC Pathway No. : 362 | 0.02 | 1.5 | No | Starting conc at 20 nM. |
AC1 acting as a Substrate in a reaction in Ajay_Bhalla_2004_Feedback_Tuning Network
Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | 1 | CaM-bind-AC1 | Ajay_Bhalla_ 2004_Feedback_ Tuning Accession No. : 78 | AC Pathway No. : 362 | 49.9995 (uM^-1 s^-1) | 1 (s^-1) | Kd(bf) = 0.02(uM) | - | Substrate AC1 CaM-Ca4
Product AC1-CaM
| | Half-max at 20 nM CaM (Tang et al JBC 266:13 8595-8603 1991 kb/kf = 20 nM = 12000 #/cell so kf = kb/12000 = kb * 8.333e-5 | 2 | Gs-bind-AC1 | Ajay_Bhalla_ 2004_Feedback_ Tuning Accession No. : 78 | AC Pathway No. : 362 | 126 (uM^-1 s^-1) | 1 (s^-1) | Kd(bf) = 0.0079(uM) | - | Substrate AC1 Gs-alpha
Product AC1-Gs
| | Half-max 8nM from Tang et al JBC266:13 8595-8603 kb/kf = 8 nM = 4800#/cell so kf = kb * 2.08e-4 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details. |
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