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Molecule Parameter List for Ca

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Ca participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000051

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_PKM
    		• 80Network
    Shared_Object_Ajay_Bhalla_2007_PKM,  PKC,  MAPK,  
    Ras,  CaM,  PKM 
    This is a non-bistable model of ERKII signaling that also incorporates PKM synthesis triggered by Ca influx. It is a simplified variant of the model of Ajay SM, Bhalla US. Eur J Neurosci. 2004 Nov;20(10):2671-80.

    Ca acting as a Molecule in      Ajay_Bhalla_2007_PKM Network
    NameAccession NamePathway NameInitial Conc.
    (uM)    		Volume
    (fL)    		Buffered
    Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
  • Shared_Object_
    Ajay_Bhalla_
    2007_PKM
    Pathway No. : 369
    		• 0.081.5No

    Ca acting as a Substrate in a reaction in      Ajay_Bhalla_2007_PKM Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
    		• PKC
    Pathway No. : 370    		0.6
    (uM^-1 s^-1)    		0.5
    (s^-1)    		Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    2CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
    		• CaM
    Pathway No. : 373    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5053(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    3CaM-bind-Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
    		• CaM
    Pathway No. : 373    		8.4848
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1.0001(uM)-Substrate
    Ca
    CaM

    Product
    CaM-Ca
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    4CaM-Ca2-bind-Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
    		• CaM
    Pathway No. : 373    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5CaM-Ca-bind-Ca
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
    		• CaM
    Pathway No. : 373    		8.4848
    (uM^-1 s^-1)    		8.4853
    (s^-1)    		Kd(bf) = 1.0001(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853

    Ca acting as a Product in a reaction in      Ajay_Bhalla_2007_PKM Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    Ca_diff
  • Ajay_Bhalla_
    2007_PKM
    Accession No. : 80
  • Shared_Object_
    Ajay_Bhalla_
    2007_PKM
    Pathway No. : 369
    		• 5
    (s^-1)    		5
    (s^-1)    		Keq = 1(uM)0.1secSubstrate
    Ca_input

    Product
    Ca


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