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Molecule Parameter List for Rb_P

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Rb_P participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences10021200

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Mammalian_cell_
    cycle
  • 85Network
    Growth CELLDIV Rb_grp 
    IE_GRP CycB_Grp Cdc20_Grp 
    Cdh1_grp E2F CycA_Grp 
    CycE_grp Early_Response_Genes Delayed_Response_Genes 
    CycD_Grp 
    This is a fairly complete mass-action reimplementation of the Novak and Tyson mammalian cell cycle model. It is inexact on two counts. First, it replaces many rather abstracted equations with mass action and Michaelis-Menten forms of enzymes. Second, it does not handle the halving of cellular volume at the division point. Within these limitations, the model does most of what the original paper shows including oscillation of the relevant molecules.

    Rb_P acting as a Molecule in  
    Mammalian_cell_cycle Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    Rb_P
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    0200No

    Rb_P acting as a Substrate for an Enzyme in  
    Mammalian_cell_cycle Network
     Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    1PP1  /
    k19_prime
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • Rb_grp
    Pathway No. : 1071
    99.99920.14explicit E-S complexSubstrate
    Rb_P

    Product
    Rb
        k19_prime is actually zero, but I do not want NaNs (numerical errors due to divide-by-zero) so I set kcat to a very small value. 7 Apr 2005. Same reasoning, now set Km to 10.
    2PP1A  /
    k19
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • Rb_grp
    Pathway No. : 1071
    10020004explicit E-S complexSubstrate
    Rb_P

    Product
    Rb
        This is part of Eqn 20. k19 = 20. It is meant to represent a dephosph step of Rb_p. rate is k19*PP1A. rate in MM form is kcat * PP1A * Rb_P / (Km + Rb_P) Assume Km << Rb_P. To do so, Km = 0.01 Then kcat = k19. 7 Apr 2005. Actually should include substrate term. Take Km = 10 >> sub. Then kcat = Km * k19 = 200 18 April. Actually substrate levels are near 10. So need to scale up. Km = 100, kcat = Km * k19 = 2000

    Rb_P acting as a Product of an Enzyme in  
    Mammalian_cell_cycle Network
     Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    1CycD  /
    k20_lambdaD
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10033004explicit E-S complexSubstrate
    Rb

    Product
    Rb_P
        With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330
    2CycD  /
    k20_lambdaD[1]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10033004explicit E-S complexSubstrate
    E2FAP.Rb

    Product
    E2FAP
    Rb_P
        With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330 The idea here is that these reactions phosphorylate the Rb protein attached to E2FAP, so that Rb_P is released and E2FAP is left.
    3CycD  /
    k20_lambdaD[2]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10033004explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FA
    Rb_P
        With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330 The idea here is that these reactions phosphorylate the Rb protein attached to E2FA, so that Rb_P is released and E2FA is left.
    4CycE  /
    k20_lambdaE
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    Rb

    Product
    Rb_P
        For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500
    5CycE  /
    k20_lambdaE[1]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    E2FAP.Rb

    Product
    E2FAP
    Rb_P
        For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500
    6CycE  /
    k20_lambdaE[2]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FA
    Rb_P
        For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500
    7CycA  /
    k20_lambdaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    Rb

    Product
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300
    8CycA  /
    k20_lambdaA[1]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    E2FAP.Rb

    Product
    E2FAP
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300
    9CycA  /
    k20_lambdaA[2]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FA
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300
    10CycB  /
    k20_lambdaB
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    Rb

    Product
    Rb_P
        With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500
    11CycB  /
    k20_lambdaB[1]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    E2FAP.Rb

    Product
    E2FAP
    Rb_P
        With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500
    12CycB  /
    k20_lambdaB[2]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    100.00250004explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FA
    Rb_P
        With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500



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