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Molecule Parameter List for Rb_P | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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| Rb_P participated as | Molecule | Sum total of | Enzyme | Substrate of an enzyme | Product of an enzyme | Substrate in Reaction | Product in Reaction |
| No. of occurrences | 1 | 0 | 0 | 2 | 12 | 0 | 0 |
Accession and Pathway Details |
| Accession Name | Accession No. | Accession Type | Pathway Link |
cycle | 85 | Network | Growth, CELLDIV, Rb_grp, IE_GRP, CycB_Grp, Cdc20_Grp, Cdh1_grp, E2F, CycA_Grp, CycE_grp, Early_Response_Genes, Delayed_Response_Genes, CycD_Grp |
| This is a fairly complete mass-action reimplementation of the Novak and Tyson mammalian cell cycle model. It is inexact on two counts. First, it replaces many rather abstracted equations with mass action and Michaelis-Menten forms of enzymes. Second, it does not handle the halving of cellular volume at the division point. Within these limitations, the model does most of what the original paper shows including oscillation of the relevant molecules. | |||
Rb_P acting as a Molecule in Mammalian_cell_cycle Network
| Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered |
| Rb_P | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 0 | 200 | No |
Rb_P acting as a Substrate for an Enzyme in Mammalian_cell_cycle Network
| Enzyme Molecule / Enzyme Activity | Accession Name | Pathway Name | Km (uM) | kcat (s^-1) | Ratio | Enzyme Type | Reagents | |
| 1 | PP1 / k19_prime | cycle Accession No. : 85 | Rb_grp Pathway No. : 1071 | 99.9992 | 0.1 | 4 | explicit E-S complex | Substrate Rb_P Product Rb |
| k19_prime is actually zero, but I do not want NaNs (numerical errors due to divide-by-zero) so I set kcat to a very small value. 7 Apr 2005. Same reasoning, now set Km to 10. | ||||||||
| 2 | PP1A / k19 | cycle Accession No. : 85 | Rb_grp Pathway No. : 1071 | 100 | 2000 | 4 | explicit E-S complex | Substrate Rb_P Product Rb |
| This is part of Eqn 20. k19 = 20. It is meant to represent a dephosph step of Rb_p. rate is k19*PP1A. rate in MM form is kcat * PP1A * Rb_P / (Km + Rb_P) Assume Km << Rb_P. To do so, Km = 0.01 Then kcat = k19. 7 Apr 2005. Actually should include substrate term. Take Km = 10 >> sub. Then kcat = Km * k19 = 200 18 April. Actually substrate levels are near 10. So need to scale up. Km = 100, kcat = Km * k19 = 2000 | ||||||||
Rb_P acting as a Product of an Enzyme in Mammalian_cell_cycle Network
| Enzyme Molecule / Enzyme Activity | Accession Name | Pathway Name | Km (uM) | kcat (s^-1) | Ratio | Enzyme Type | Reagents | |
| 1 | CycD / k20_lambdaD | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3300 | 4 | explicit E-S complex | Substrate Rb Product Rb_P |
| With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330 | ||||||||
| 2 | CycD / k20_lambdaD[1] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3300 | 4 | explicit E-S complex | Substrate E2FAP.Rb Product E2FAP Rb_P |
| With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330 The idea here is that these reactions phosphorylate the Rb protein attached to E2FAP, so that Rb_P is released and E2FAP is left. | ||||||||
| 3 | CycD / k20_lambdaD[2] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3300 | 4 | explicit E-S complex | Substrate E2FA.Rb Product E2FA Rb_P |
| With a low Km, rate ~ kcat. Here we have rate = k20 * lambda_d = 10 * 3.3 = 33. 7 Apr 2005. Actually should have the substrate term in here. Use the form Km >> substrate, so rate = kcat * sub * enz / Km so kcat = Km * k20 * lambda_d = 10 * 10 * 3.3 = 330 The idea here is that these reactions phosphorylate the Rb protein attached to E2FA, so that Rb_P is released and E2FA is left. | ||||||||
| 4 | CycE / k20_lambdaE | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate Rb Product Rb_P |
| For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500 | ||||||||
| 5 | CycE / k20_lambdaE[1] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate E2FAP.Rb Product E2FAP Rb_P |
| For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500 | ||||||||
| 6 | CycE / k20_lambdaE[2] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate E2FA.Rb Product E2FA Rb_P |
| For Km ~ 0, rate ~ kcat. rate = k20 * lambdaE = 10 * 5 7 Apr 2005. Actually need to put in substrate term too. Let Km = 10 >> sub. Then, rate ~ kcat * sub * prd /Km so kcat = Km * k20 * lambdaE = 10 * 10 * 5 = 500 | ||||||||
| 7 | CycA / k20_lambdaA | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3000 | 4 | explicit E-S complex | Substrate Rb Product Rb_P |
| Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300 | ||||||||
| 8 | CycA / k20_lambdaA[1] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3000 | 4 | explicit E-S complex | Substrate E2FAP.Rb Product E2FAP Rb_P |
| Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300 | ||||||||
| 9 | CycA / k20_lambdaA[2] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100 | 3000 | 4 | explicit E-S complex | Substrate E2FA.Rb Product E2FA Rb_P |
| Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300 | ||||||||
| 10 | CycB / k20_lambdaB | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate Rb Product Rb_P |
| With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500 | ||||||||
| 11 | CycB / k20_lambdaB[1] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate E2FAP.Rb Product E2FAP Rb_P |
| With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500 | ||||||||
| 12 | CycB / k20_lambdaB[2] | cycle Accession No. : 85 | CELLDIV Pathway No. : 1070 | 100.002 | 5000 | 4 | explicit E-S complex | Substrate E2FA.Rb Product E2FA Rb_P |
| With Km ~ 0, rate ~ kcat. Here rate = k20 * lambdaB = 10 * 5 7 Apr 2005. Changed to include substrate term. Use Km = 10 >> sub, so kcat = Km * k20 * lambdaB = 10 * 10 * 5 = 500 | ||||||||
color.