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Molecule Parameter List for CycA

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CycA participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences10131411

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Mammalian_cell_
    cycle
  • 85Network
    Growth CELLDIV Rb_grp 
    IE_GRP CycB_Grp Cdc20_Grp 
    Cdh1_grp E2F CycA_Grp 
    CycE_grp Early_Response_Genes Delayed_Response_Genes 
    CycD_Grp 
    This is a fairly complete mass-action reimplementation of the Novak and Tyson mammalian cell cycle model. It is inexact on two counts. First, it replaces many rather abstracted equations with mass action and Michaelis-Menten forms of enzymes. Second, it does not handle the halving of cellular volume at the division point. Within these limitations, the model does most of what the original paper shows including oscillation of the relevant molecules.

    CycA acting as a Molecule in  
    Mammalian_cell_cycle Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CycA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    0200No
    rate = k4.Gamma_A * [CycA] * [Cdh1]/(J4 + [Cdh1]) J4 = 0.01 k4 = kcat = 40

    CycA acting as an Enzyme in  
    Mammalian_cell_cycle Network
     Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    1CycA /
    k20_lambdaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    Rb

    Product
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300
    2CycA /
    k21_phiE_A
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    9.9996825004explicit E-S complexSubstrate
    PP1A

    Product
    PP1
        phiE is also used for the reaction catalyzed by A. So rates are identical to k21_phiE
    3CycA /
    Cdh1_CycA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    0.01124explicit E-S complexSubstrate
    Cdh1

    Product
    Cdh1_i
        J4 = Km = 0.01 k4 = 40. GammaA = 0.3 kcat = k4 * GammaA = 12
    4CycA /
    A_phosph_E2F
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    9.99992104explicit E-S complexSubstrate
    E2FA

    Product
    E2FAP
        Rate equn has form [CycA].[E2F].k23 k23 = 1 MM equn has form [CycA].[E2F].kcat/(Km + E2F) So, we set kcat = Km * k23 where Km >> E2F 25 Mar. Better: Use explicit enz form. rate = k3.k1/k2 if k3 << k2. Let k3 = 1, k2 = 10, so we get k1 = k23 * 10 = 10. 6 Apr. Problem with explicit form is that the enz-substrate complex may affect the levels of the CycA, B etc. Back to MM.
    5CycA /
  • A_phosph_
    E2FA.Rb
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    9.99992104explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FAP.Rb
        Rate equn has form [CycA].[E2F].k23 k23 = 1 MM equn has form [CycA].[E2F].kcat/(Km + E2F) So, we set kcat = Km * k23 where Km >> E2F 25 March 2005 Use explicit form. rate = k23 = 1 = k3*k1/k2 where k3 << k2 So k3 = 1, k2 = 10, k1 = 10. 6 Apr 2005. Back to MM form because enz complex formation is depleting CycA, B etc.
    6CycA /
    Ak6_etaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    CycA_Kip1

    Product
    CycA
    degraded
        See Ak6_etaE
    7CycA /
    k8_CycA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    0.124explicit E-S complexSubstrate
    CycE

    Product
    degraded
    8CycA /
    k6_E_etaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    CycE_Kip1

    Product
    CycE
    degraded
        See notes for k6_E_etaE. Explicit rates had been k1 = 500, k2 = 10, k3 = 1 but this gave a very low Km. So, back to MM: etaA = 0.5 so kcat = 500, Km = 10 as for k6_E_etaE
    9CycA /
    k6_D_etaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    CycD_Kip1

    Product
    CycD
    degraded
        k3.k1/k2 = k6.etaA = 100*0.5 = 50 Also k3 << k2. Assume ratio is 10. Let k3 be reasonable, say 1. Then k2 = 10, k1 = 500. 6 April 2005: The above rates are bad because they give a very low Km and too much E.S. complex. So, back to MM: Km >> substrate, so Km = 10. Then kcat = Km * k6 * etaA = 10 * 100 * 0.5 = 500.
    10CycA /
    k8_CycA_Kip1
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    0.124explicit E-S complexSubstrate
    CycE_Kip1

    Product
    Kip1
    degraded
    11CycA /
    k6_kip1_A
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    Kip1

    Product
    degraded_kip
        k3.k1/k2 = k6.etaA = 100*0.5 = 50 Also k3 << k2. Assume ratio is 10. Let k3 be reasonable, say 1. Then k2 = 10, k1 = 500. 6 April 2005: The above rates are bad because they give a very low Km and too much E.S. complex. So, back to MM: Km >> substrate, so Km = 10. Then kcat = Km * k6 * etaA = 10 * 100 * 0.5 = 500.
    12CycA /
    k20_lambdaA[1]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    E2FAP.Rb

    Product
    E2FAP
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300
    13CycA /
    k20_lambdaA[2]
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10030004explicit E-S complexSubstrate
    E2FA.Rb

    Product
    E2FA
    Rb_P
        Km ~ 0, so rate ~ kcat. Here rate = k20 * lambdaA = 10 * 3 7 Apr 2005: Fix it: rate should have substrate term in it. Set Km = 10 >> substrate. Then, kcat = Km * k20 * lambdaA = 10 * 10 * 3 = 300

    CycA acting as a Substrate for an Enzyme in  
    Mammalian_cell_cycle Network
    Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    Cdc20  /
    Cdc20_deg_CycA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    102004explicit E-S complexSubstrate
    CycA

    Product
    degraded
    Rate comes in as k30 = 20 Rate = [Cdc20]*[CycA] * k30. To put in MM form: Rate = [Cdc20]*[CycA] * kcat / (Km + [CycA]) where kcat = k30 * Km and Km >> [CycA]. Put Km = 1000, so kcat = 20000 25 March: use explicit enz form. Use rate = k3*k1/k2 = 20, which works if k2 >> k3. Then let k3 = 1, k2 = 10, k1 becomes 200 7 Apr 2005: Above won't work because of low Km consuming too much of the Cdc20 in the complex form. So use Km = 10, kcat = 200.

    CycA acting as a Product of an Enzyme in  
    Mammalian_cell_cycle Network
     Enzyme Molecule /
    Enzyme Activity
    Accession NamePathway NameKm (uM)kcat (s^-1)RatioEnzyme TypeReagents
    1CycE  /
    Ak6_etaE
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    CycA_Kip1

    Product
    CycA
    degraded
        Rate = V6 * [CycD_Kip1]. 6 Apr 2005. Rates were k1 = 500, k2 = 10, k3 = 1 in explicit E.S reaction form. Changed to MM as Km was too low. New values: Km = 10 kcat = Km * k6 * etaE = 500.
    2CycA  /
    Ak6_etaA
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    10.00025004explicit E-S complexSubstrate
    CycA_Kip1

    Product
    CycA
    degraded
        See Ak6_etaE
    3CycB  /
    Ak6_etaB
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    9.9999210004explicit E-S complexSubstrate
    CycA_Kip1

    Product
    CycA
    degraded
        See Ak6_etaE
    4E2FA  /
    k29
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CELLDIV
    Pathway No. : 1070
    1000.02504explicit E-S complexSubstrate
    Mass_dup

    Product
    CycA
        Represented as eps*k29*[E2FA]*[mass], where k29 is 0.05 Split into two steps, this one deals with the E2FA term. rate = Mass_dup * E2FA * kcat / (Km + Mass_dup) Note that Mass_dup will not change. Let Km >> Mass_dup and kcat = k29 * Km. then rate ~ Mass_dup * E2FA * k29 * Km / Km

    CycA acting as a Substrate in a reaction in  
    Mammalian_cell_cycle Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    k25
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CycA_Grp
    Pathway No. : 1077
    999.996
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 0.01(uM)-Substrate
    CycA
    Kip1

    Product
    CycA_Kip1

    CycA acting as a Product in a reaction in  
    Mammalian_cell_cycle Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    k_prime6
  • Mammalian_cell_
    cycle

    Accession No. : 85
  • CycA_Grp
    Pathway No. : 1077
    10
    (s^-1)
    0
    (uM^-1 s^-1)
    --Substrate
    CycA_Kip1

    Product
    CycA
    degraded



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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