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Molecule Parameter List for k14_enz | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color. | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| Statistics | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| k14_enz participated as | Molecule | Sum total of | Enzyme | Substrate of an enzyme | Product of an enzyme | Substrate in Reaction | Product in Reaction |
| No. of occurrences | 1 | 0 | 1 | 0 | 0 | 0 | 0 |
Accession and Pathway Details |
| Accession Name | Accession No. | Accession Type | Pathway Link |
cycle | 85 | Network | Growth, CELLDIV, Rb_grp, IE_GRP, CycB_Grp, Cdc20_Grp, Cdh1_grp, E2F, CycA_Grp, CycE_grp, Early_Response_Genes, Delayed_Response_Genes, CycD_Grp |
| This is a fairly complete mass-action reimplementation of the Novak and Tyson mammalian cell cycle model. It is inexact on two counts. First, it replaces many rather abstracted equations with mass action and Michaelis-Menten forms of enzymes. Second, it does not handle the halving of cellular volume at the division point. Within these limitations, the model does most of what the original paper shows including oscillation of the relevant molecules. | |||
k14_enz acting as a Molecule in Mammalian_cell_cycle Network
| Name | Accession Name | Pathway Name | Initial Conc. (uM) | Volume (fL) | Buffered |
| k14_enz | cycle Accession No. : 85 | Cdc20_Grp Pathway No. : 1074 | 1 | 200 | Yes |
k14_enz acting as an Enzyme in Mammalian_cell_cycle Network
| Enzyme Molecule / Enzyme Activity | Accession Name | Pathway Name | Km (uM) | kcat (s^-1) | Ratio | Enzyme Type | Reagents |
| k14_enz / k14 | cycle Accession No. : 85 | Cdc20_Grp Pathway No. : 1074 | 0.00500008 | 2.5 | 4 | explicit E-S complex | Substrate Cdc20 Product Cdc20notA |
| Represented as k14.[Cdc20] / (J4 + [Cdc20]) But I suspect it should be J14. k14 = 2.5 J14 = 0.005 If we set enz = 1, Km = J14, kcat = k14, this equation applies. | |||||||
color.