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Reaction List for pathway CaM (Pathway Number 122) in Accession Osc_Ca_IP3metabolism (Accession Number 24) | Entries are grouped according to Pathway Number and they are alternately color coded using  and  color.
Further ordering can be done to the table header.   indicates that ordering is done according to ascending or descending order.
Keq is calculated only for first order reactions.
Kd is calculated only for second order reactions. [nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules] |
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Reaction
Name | Pathway Name /
Pathway No. | Kf | Kb | Kd | tau | Reagents | | 1 | CaM-TR2-bind-Ca | CaM
Pathway No. 122 | 72
(uM^-2 s^-1) | 72
(s^-1) | Kd(af) = 1(uM) | - | Substrate:
CaM
Ca
Ca
Products:
CaM-TR2-Ca2
| | | We use the Martin et al 1985 Eur J Biochem 151(3):543-550 rates here, plus the Drabikowski and Brzeska 1982 JBC 257(19):11584-11590 binding consts. All are scaled by 3X to cell temperature. kf = 2e-10 kb = 72 Stemmer & Klee 1994 Biochem 33:6859-6866 have values of : K1=.9, K2=1.1. Assume 1.0uM for both | | 2 | CaM-TR2-Ca2-bind
-Ca | CaM
Pathway No. 122 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate:
CaM-TR2-Ca2
Ca
Products:
CaM-Ca3
| | | Stemmer and Klee 1994 Biochem 33:6859-6866 K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 | | 3 | CaM-Ca3-bind-Ca | CaM
Pathway No. 122 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate:
CaM-Ca3
Ca
Products:
CaM-Ca4
| | | Use K3 = 21.5 uM here from Stemmer and Klee table 3. Stemmer and Klee 1994 Biochem 33:6859-6866 kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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