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Molecule Parameter List for CaM-Ca3 | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | | CaMKII_model3 | 63 | Network |
Shared_Object_CaMKII_model3, CaMKII, CaM,
PP1, PP2B, PP1_PSD,
AC, PKA | | This is the complete model of CaMKII bistability, model 3. It exhibits bistability in CaMKII activation due to autophosphorylation at the PSD and local saturation of PP1. This version of model 3 includes PKA regulatory input. This has little effect on the deterministic calculations, but the PKA pathway introduces a lot of noise which causes a difference in stochastic runs. |
CaM-Ca3 acting as a Molecule in CaMKII_model3 Network
CaM-Ca3 acting as a Substrate in a reaction in CaMKII_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | CaM-Ca3-bind-Ca | CaMKII_model3
Accession No. : 63 | Shared_Object_
CaMKII_model3
Pathway No. : 263 | 0.465
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 21.5054(uM) | - | Substrate
Ca
CaM-Ca3
Product
CaM-Ca4
| | Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10 |
CaM-Ca3 acting as a Product in a reaction in CaMKII_model3 Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | CaM-TR2-Ca2-bind
-Ca | CaMKII_model3
Accession No. : 63 | CaM
Pathway No. : 265 | 3.6
(uM^-1 s^-1) | 10
(s^-1) | Kd(bf) = 2.7778(uM) | - | Substrate
Ca
CaM-TR2-Ca2
Product
CaM-Ca3
| | K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10 |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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