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Molecule Parameter List for CaM-Ca2

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca2 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences2500004949

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
  • 81NetworkShared_Object_Ajay_bhalla_2007_ReacDiff1_1e-12 
    PKC MAPK Ras CaM PKM chain kinetics PKC MAPK Ras CaM PKM kinetics[1] 
    PKC MAPK Ras CaM PKM kinetics[2] PKC MAPK Ras CaM PKM kinetics[3] 
    PKC MAPK MAPK Ras CaM PKM kinetics[4] PKC MAPK Ras CaM PKM 
    kinetics[5] PKC MAPK Ras kinetics[6] CaM PKM PKC MAPK Ras 
    CaM PKM kinetics[7] PKC Ras CaM PKM kinetics[8] PKC MAPK 
    Ras CaM PKM kinetics[9] PKC MAPK Ras CaM PKM kinetics[10] 
    PKC MAPK Ras CaM PKM kinetics[11] PKC MAPK Ras CaM PKM kinetics[12] 
    PKC MAPK Ras CaM PKM kinetics[13] PKC MAPK Ras CaM PKM kinetics[14] 
    PKC MAPK Ras CaM PKM kinetics[15] PKC MAPK Ras CaM PKM kinetics[16] 
    PKC MAPK Ras CaM PKM kinetics[17] PKC MAPK Ras CaM PKM kinetics[18] 
    PKC MAPK Ras CaM PKM kinetics[19] PKC MAPK Ras CaM PKM kinetics[20] 
    PKC MAPK Ras CaM PKM kinetics[21] PKC MAPK Ras CaM PKM kinetics[22] 
    PKC MAPK Ras CaM PKM kinetics[23] PKC MAPK Ras CaM PKM 
    This is a 25-compartment reaction-diffusion version of the Ajay_Bhalla_2007_PKM model. The original single-compartment model is repeated 25 times. In addition, a subset (27 out of 42) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. For D = 1e-12 m^2/sec (i.e., 1 micron^2/sec ) the kf and kb of this reaction for these 10 micron compartments are both 0.01/sec. For D = 1e-13 m^2/sec (i.e., 0.1 micron^2/sec ) the kf and kb are 0.001/sec.
    The stimulus file pkm_mapk22_diff_1e-12_Fig4A which was used for the model to replicate Figure 4A from the paper.
    This stimulus file pkm_mapk22_diff_1e-12_Fig4G which was used for the model to replicate Figure 4G from the paper

    CaM-Ca2 acting as a Molecule in  
    Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 379
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 386
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 392
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 398
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 405
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 411
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 418
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 423
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 428
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 434
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 440
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 446
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 452
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 458
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 464
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 470
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 476
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 482
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 488
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 494
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 500
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 506
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 512
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 518
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.
    CaM-Ca2
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 524
    01.5No
    This is the intermediate where the TR2 end (the high-affinity end) has bound the Ca but the TR1 end has not.

    CaM-Ca2 acting as a Substrate in a reaction in  
    Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    2CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 379
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    3diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    4CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 386
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    6CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 392
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    7diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    8CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 398
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    9diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    10CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 405
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    11diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    12CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 411
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    13diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    14CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 418
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    15diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    16CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 423
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    17diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    18CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 428
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    19diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    20CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 434
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    21diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    22CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 440
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    23diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    24CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 446
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    25diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    26CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 452
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    27diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    28CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 458
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    29diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    30CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 464
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    31diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    32CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 470
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    33diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    34CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 476
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    35diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    36CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 482
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    37diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    38CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 488
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    39diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    40CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 494
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    41diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    42CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 500
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    43diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    44CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 506
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    45diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    46CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 512
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    47diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    48CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 518
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    49CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 524
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10

    CaM-Ca2 acting as a Product in a reaction in  
    Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    2CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 379
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    3diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    4CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 386
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    5diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    6CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 392
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    7diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    8CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 398
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    9diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    10CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 405
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    11diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    12CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 411
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    13diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    14CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 418
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    15diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    16CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 423
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    17diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    18CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 428
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    19diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    20CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 434
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    21diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    22CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 440
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    23diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    24CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 446
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    25diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    26CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 452
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    27diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    28CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 458
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    29diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    30CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 464
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    31diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    32CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 470
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    33diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    34CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 476
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    35diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    36CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 482
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    37diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    38CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 488
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    39diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    40CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 494
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    41diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    42CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 500
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    43diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    44CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 506
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    45diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    46CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 512
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    47diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Pathway No. : 375
  • 0.01
    (s^-1)
    0.01
    (s^-1)
    Keq = 1(uM)50secSubstrate
    CaM-Ca2

    Product
    CaM-Ca2
    48CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 518
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853
    49CaM-Ca-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12

    Accession No. : 81
  • CaM
    Pathway No. : 524
    8.4851
    (uM^-1 s^-1)
    8.4853
    (s^-1)
    Kd(bf) = 1(uM)-Substrate
    Ca
    CaM-Ca

    Product
    CaM-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !) 19 May 2006. Splitting the old CaM-TR2-bind-Ca reaction into two steps, each binding 1 Ca. This improves numerical stability and is conceptually better too. Overall rates are the same, so each kf and kb is the square root of the earlier ones. So kf = 1.125e-4, kb = 8.4853



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