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Molecule Parameter List for CaM-Ca4

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network. The text color of a molecule is highlighted by color.

Statistics

CaM-Ca4 participated as	Molecule	Sum total of	Enzyme	Substrate of an enzyme	Product of an enzyme	Substrate in Reaction	Product in Reaction
No. of occurrences	1	0	0	0	0	3	1

Accession and Pathway Details

Accession Name	Accession No.	Accession Type	Pathway Link
CaMKII_2003	49	Network	Shared_Object_CaMKII_2003,  CaMKII,  CaM,   PP1,  PP2B
Model of regulation of CaMKII by Calcium, including parallel excitatory input from CaM and inhibitory input from PP1 as regulated by Calcineurin and PKA. Cell type: neuronal. Bhalla US. Biophys J. 2004 Aug;87(2):733-44.

CaM-Ca4 acting as a Molecule in  CaMKII_2003 Network

Name	Accession Name	Pathway Name	Initial Conc. (uM)	Volume (fL)	Buffered
CaM-Ca4	CaMKII_2003 Accession No. : 49	Shared_Object_ CaMKII_2003 Pathway No. : 201	0	1000	No

CaM-Ca4 acting as a Substrate in a reaction in  CaMKII_2003 Network

Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.

	Name	Accession Name	Pathway Name	Kf	Kb	Kd	tau	Reagents
1	CaMKII-bind-CaM	CaMKII_2003 Accession No. : 49	CaMKII Pathway No. : 202	49.9998 (uM^-1 s^-1)	5 (s^-1)	Kd(bf) = 0.1(uM)	-	Substrate CaM-Ca4 CaMKII Product CaMKII-CaM
	This is tricky. There is some cooperativity here arising from interactions between the subunits of the CAMKII holoenzyme. However, the stoichiometry is 1. Kb/Kf = 6e4 #/cell. Rate is fast (see Hanson et al Neuron 12 943-956 1994) so lets say kb = 10. This gives kf = 1.6667e-4 H&S AnnRev Biochem 92 give tau for dissoc as 0.2 sec at low Ca, 0.4 at high. Low Ca = 100 nM = physiol.
2	CaMK-thr286-bind -CaM	CaMKII_2003 Accession No. : 49	CaMKII Pathway No. : 202	1000.2 (uM^-1 s^-1)	0.1 (s^-1)	Kd(bf) = 0.0001(uM)	-	Substrate CaM-Ca4 CaMKII-thr286 Product CaMKII-thr286*-C aM
	Affinity is up 1000X. Time to release is about 20 sec, so the kb is OK at 0.1 This makes Kf around 1.6666e-3
3	CaMCa4-bind-CaNA B	CaMKII_2003 Accession No. : 49	PP2B Pathway No. : 205	600 (uM^-1 s^-1)	1 (s^-1)	Kd(bf) = 0.0017(uM)	-	Substrate CaM-Ca4 CaNAB-Ca4 Product CaMCa4-CaNAB

CaM-Ca4 acting as a Product in a reaction in  CaMKII_2003 Network

Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.

Name	Accession Name	Pathway Name	Kf	Kb	Kd	tau	Reagents
CaM-Ca3-bind-Ca	CaMKII_2003 Accession No. : 49	CaM Pathway No. : 203	0.465 (uM^-1 s^-1)	10 (s^-1)	Kd(bf) = 21.5054(uM)	-	Substrate Ca CaM-Ca3 Product CaM-Ca4
Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10