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Molecule Parameter List for Ca

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
Ca participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences1000061

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_Bhalla_
    2007_Bistable
  • 79Network
    Shared_Object_Ajay_Bhalla_2007_Bistable PKC PLA2 
    MAPK Ras CaM 
    This is a model of ERKII signaling which is bistable due to feedback. The feedback occurs through ERKII phosphorylation of phospholipase A2 (PLA2), leading to increased production of arachidonic acid (AA), which activates protein kinase C (PKC) which activates c-Raf which is upstream of ERKII.
    The model is a highly simplified variant of more detailed bistable models of MAPK signaling (Bhalla US, Iyengar R. Science. 1999 Jan 15;283(5400):381-7, Ajay SM, Bhalla US. Eur J Neurosci. 2004 Nov;20(10):2671-80)

    Ca acting as a Molecule in  
    Ajay_Bhalla_2007_Bistable Network
    NameAccession NamePathway NameInitial Conc.
    (uM)
    Volume
    (fL)
    Buffered
    Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • Shared_Object_
    Ajay_Bhalla_
    2007_Bistable

    Pathway No. : 363
  • 0.08125.7No

    Ca acting as a Substrate in a reaction in  
    Ajay_Bhalla_2007_Bistable Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1PKC-act-by-Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • PKC
    Pathway No. : 364
    0.6
    (uM^-1 s^-1)
    0.5
    (s^-1)
    Kd(bf) = 0.8333(uM)-Substrate
    Ca
    PKC-cytosolic

    Product
    PKC-Ca
      Need est of rate of assoc of Ca and PKC. Assume it is fast The original parameter-searched kf of 439.4 has been scaled by 1/6e8 to account for change of units to n. Kf now 8.16e-7, kb=.6085 Raised kf to 1e-6 to match Ca curve, kb to .5
    2PLA2-Ca-act
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • PLA2
    Pathway No. : 365
    1
    (uM^-1 s^-1)
    0.1
    (s^-1)
    Kd(bf) = 0.1(uM)-Substrate
    Ca
    PLA2-cytosolic

    Product
    PLA2-Ca*
      Leslie and Channon BBA 1045 (1990) 261-270 fig6 pp267.
    3PLA2*-Ca-act
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • PLA2
    Pathway No. : 365
    6
    (uM^-1 s^-1)
    0.1
    (s^-1)
    Kd(bf) = 0.0167(uM)-Substrate
    Ca
    PLA2*

    Product
    PLA2*-Ca
      To start off, same kinetics as the PLA2-Ca-act direct pathway. Oops ! Missed out the Ca input to this pathway first time round. Let's raise the forward rate about 3x to 5e-6. This will let us reduce the rather high rates we have used for the kenz on PLA2*-Ca. In fact, it may be that the rates are not that different, just that this pathway for getting the PLA2 to the memb is more efficien....
    4CaM-TR2-bind-Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    72.0009
    (uM^-2 s^-1)
    72
    (s^-1)
    Kd(af) = 1(uM)-Substrate
    Ca
    Ca
    CaM

    Product
    CaM-TR2-Ca2
      Lets use the fast rate consts here. Since the rates are so different, I am not sure whether the order is relevant. These correspond to the TR2C fragment. We use the Martin et al rates here, plus the Drabicowski binding consts. All are scaled by 3X to cell temp. kf = 2e-10 kb = 72 Stemmer & Klee: K1=.9, K2=1.1. Assume 1.0uM for both. kb/kf=3.6e11. If kb=72, kf = 2e-10 (Exactly the same !)....
    5
  • CaM-TR2-Ca2-bind
    -Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    3.6
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-TR2-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    6CaM-Ca3-bind-Ca
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • CaM
    Pathway No. : 368
    0.465
    (uM^-1 s^-1)
    10
    (s^-1)
    Kd(bf) = 21.5053(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    Ca acting as a Product in a reaction in  
    Ajay_Bhalla_2007_Bistable Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
    NameAccession NamePathway NameKfKbKdtauReagents
    Ca_diff
  • Ajay_Bhalla_
    2007_Bistable

    Accession No. : 79
  • Shared_Object_
    Ajay_Bhalla_
    2007_Bistable

    Pathway No. : 363
  • 2
    (s^-1)
    2
    (s^-1)
    Keq = 1(uM)0.25secSubstrate
    Ca_input

    Product
    Ca



    Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
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