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Molecule Parameter List for Internal_L.EGFR | The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by  color. | | Statistics |
| Internal_L.EGFR participated as | Molecule | Sum total of | Enzyme | Substrate of an enzyme | Product of an enzyme | Substrate in Reaction | Product in Reaction | | No. of occurrences | 1 | 0 | 0 | 0 | 0 | 0 | 1 |
Accession and Pathway Details | |
| Accession Name | Accession No. | Accession Type | Pathway Link | Synaptic_
Network | 16 | Network |
Shared_Object_Synaptic_Network, PKC, PLA2,
PLCbeta, Gq, MAPK,
Ras, EGFR, Sos,
PLC_g, CaMKII, CaM,
PP1, PP2B, PKA,
AC, CaRegulation | This model is an annotated version of the synaptic signaling network.
The primary reference is Bhalla US and Iyengar R. Science (1999) 283(5400):381-7 but several of the model pathways have been updated.
Bhalla US Biophys J. 2002 Aug;83(2):740-52
Bhalla US J Comput Neurosci. 2002 Jul-Aug;13(1):49-62 |
Internal_L.EGFR acting as a Molecule in Synaptic_Network Network
| Name | Accession Name | Pathway Name | Initial Conc.
(uM) | Volume
(fL) | Buffered | | Internal_L.EGFR | Synaptic_
Network
Accession No. : 16 | EGFR
Pathway No. : 77 | 0 | 1000 | No | | The internalized and inactive ligand-bound EGFR. There is lots of interesting cell biology which we are ignoring here. |
Internal_L.EGFR acting as a Product in a reaction in Synaptic_Network Network
| Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated.
Kd for higher order reaction are not consider. |
| Name | Accession Name | Pathway Name | Kf | Kb | Kd | tau | Reagents | | Internalize | Synaptic_
Network
Accession No. : 16 | EGFR
Pathway No. : 77 | 0.002
(s^-1) | 0.0003
(s^-1) | Keq = 0.165(uM) | 434.783sec | Substrate
L.EGFR
Product
Internal_L.EGFR
| | See Helin and Beguinot JBC 266:13 1991 pg 8363-8368. In Fig 3 they have internalization tau about 10 min, equil at about 20% EGF available. So kf = 4x kb, and 1/(kf + kb) = 600 sec so kb = 1/3K = 3.3e-4, and kf = 1.33e-3. This doesn't take into account the unbound receptor, so we need to push the kf up a bit, to 0.002 This reaction is treated as reversible, thereby making the approximation that the re-insertion of EGFR into the membrane is handled by the same process going backwards. |
| Database compilation and code copyright (C) 2022, Upinder S. Bhalla and NCBS/TIFR
This Copyright is applied to ensure that the contents of this database remain freely available. Please see FAQ for details. |
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