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Molecule Parameter List for CaM-Ca3

The statistics table lists the distribution of a molecule acting either as a substrate, product, enzyme or as a molecule within the network.
The text color of a molecule is highlighted by color.
Statistics
CaM-Ca3 participated asMoleculeSum total ofEnzymeSubstrate of an enzymeProduct of an enzymeSubstrate in ReactionProduct in Reaction
No. of occurrences2500004949

Accession and Pathway Details
Accession NameAccession No.Accession TypePathway Link
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    		• 81NetworkShared_Object_Ajay_bhalla_2007_ReacDiff1_1e-12,  
    PKC,  MAPK,  Ras,  CaM,  PKM,  chain,  kinetics,  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[1],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[2],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[3],  
    PKC,  MAPK,  MAPK,  Ras,  CaM,  PKM,  kinetics[4],  PKC,  MAPK,  Ras,  CaM,  PKM,  
    kinetics[5],  PKC,  MAPK,  Ras,  kinetics[6],  CaM,  PKM,  PKC,  MAPK,  Ras,  
    CaM,  PKM,  kinetics[7],  PKC,  Ras,  CaM,  PKM,  kinetics[8],  PKC,  MAPK,  
    Ras,  CaM,  PKM,  kinetics[9],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[10],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[11],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[12],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[13],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[14],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[15],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[16],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[17],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[18],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[19],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[20],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[21],  PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[22],  
    PKC,  MAPK,  Ras,  CaM,  PKM,  kinetics[23],  PKC,  MAPK,  Ras,  CaM,  PKM 
    This is a 25-compartment reaction-diffusion version of the Ajay_Bhalla_2007_PKM model. The original single-compartment model is repeated 25 times. In addition, a subset (27 out of 42) molecules can diffuse between compartments. Diffusion is implemented as a reaction between corresponding molecules in neighboring compartments. For D = 1e-12 m^2/sec (i.e., 1 micron^2/sec ) the kf and kb of this reaction for these 10 micron compartments are both 0.01/sec. For D = 1e-13 m^2/sec (i.e., 0.1 micron^2/sec ) the kf and kb are 0.001/sec.
    The stimulus file pkm_mapk22_diff_1e-12_Fig4A which was used for the model to replicate Figure 4A from the paper.
    This stimulus file pkm_mapk22_diff_1e-12_Fig4G which was used for the model to replicate Figure 4G from the paper

    CaM-Ca3 acting as a Molecule in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    NameAccession NamePathway NameInitial Conc.
    (uM)    		Volume
    (fL)    		Buffered
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		01.5No
    CaM-Ca3
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		01.5No

    CaM-Ca3 acting as a Substrate in a reaction in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    2diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    3CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    4diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    5CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    6diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    7CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    8diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    9CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    10diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    11CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    12diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    13CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    14diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    15CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    16diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    17CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    18diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    19CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    20diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    21CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    22diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    23CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    24diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    25CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    26diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    27CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    28diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    29CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    30diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    31CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    32diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    33CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    34diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    35CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    36diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    37CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    38diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    39CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    40diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    41CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    42diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    43CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    44diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    45CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    46diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    47CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10
    48diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    49CaM-Ca3-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		0.465
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 21.5051(uM)-Substrate
    Ca
    CaM-Ca3

    Product
    CaM-Ca4
      Use K3 = 21.5 uM here from Stemmer and Klee table 3. kb/kf =21.5 * 6e5 so kf = 7.75e-7, kb = 10

    CaM-Ca3 acting as a Product in a reaction in      Ajay_bhalla_2007_ReacDiff1_1e-12 Network
    Kd is calculated only for second order reactions, like nA+nB <->nC or nA<->nC+nD, where n is number and A,B,C,D are molecules, where as for first order reactions Keq is calculated. Kd for higher order reaction are not consider.
     NameAccession NamePathway NameKfKbKdtauReagents
    1diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    2CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 379    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    3diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    4CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 386    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    5diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    6CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 392    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    7diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    8CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 398    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    9diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    10CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 405    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    11diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    12CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 411    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    13diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    14CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 418    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    15diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    16CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 423    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    17diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    18CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 428    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    19diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    20CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 434    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    21diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    22CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 440    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    23diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    24CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 446    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    25diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    26CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 452    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    27diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    28CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 458    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    29diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    30CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 464    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    31diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    32CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 470    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    33diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    34CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 476    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    35diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    36CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 482    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    37diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    38CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 488    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    39diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    40CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 494    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    41diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    42CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 500    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    43diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    44CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 506    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    45diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    46CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 512    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    47diff
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
  • Shared_Object_
    Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Pathway No. : 375
    		• 0.01
    (s^-1)    		0.01
    (s^-1)    		Keq = 1(uM)50secSubstrate
    CaM-Ca3

    Product
    CaM-Ca3
    48CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 518    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10
    49CaM-Ca2-bind-Ca
  • Ajay_bhalla_
    2007_ReacDiff1_
    1e-12
    Accession No. : 81
    		• CaM
    Pathway No. : 524    		3.6
    (uM^-1 s^-1)    		10
    (s^-1)    		Kd(bf) = 2.7778(uM)-Substrate
    Ca
    CaM-Ca2

    Product
    CaM-Ca3
      K3 = 21.5, K4 = 2.8. Assuming that the K4 step happens first, we get kb/kf = 2.8 uM = 1.68e6 so kf =6e-6 assuming kb = 10


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